Page 113 - Determinants and Their Applications in Mathematical Physics
P. 113

98   4. Particular Determinants

          Proof. Equation (4.7.1) together with its first (n − 1) derivatives form
          a set of n homogeneous equations in the n coefficients λ r . The condition
          that not all the λ r be zero is that the determinant of the coefficients of the
          λ r be zero, that is,


                              y 1    y 2   ···
                                                 y n
                              y      y     ···   y


                               1      2           n    =0

                             ...........................
                             (n−1)  (n−1)
                            y      y            (n−1)
                             1      2      ··· y n
          for all values of x, which proves the theorem.
            This determinant is known as the Wronskian of the n functions y r and is
          denoted by W(y 1 ,y 2 ,...,y n ), which can be abbreviated to W n or W where
          there is no risk of confusion. After transposition, W n can be expressed in
          column vector notation as follows:



                     W n = W(y 1 ,y 2 ,...,y n )= CC C ··· C  (n−1)

          where

                                                  .                  (4.7.2)
                                                 T
                                 C = y 1 y 2 ··· y n
          If W n  = 0, identically the n functions are linearly independent.
          Theorem 4.25. If t = t(x),
                        W(ty 1 ,ty 2 ,...,ty n )= t W(y 1 ,y 2 ,...,y n ).
                                            n
          Proof.



                  W(ty 1 ,ty 2 ,...,ty n )= (tC)(tC) (tC) ··· (tC)  (n−1)


                                    = K 1 K 2 K 3 ··· K n ,


          where
                                                         d
                                          j−1
                                  (j−1)
                        K j =(tC)     = D    (tC),  D =    .
                                                        dx
          Recall the Leibnitz formula for the (j − 1)th derivative of a product and
          perform the following column operations:
                         j−1
                              j − 1      1
              K = K j + t            D s     K j−s ,  j = n, n − 1,..., 3.2.

                j               s         t
                         s=1
                    j−1
                         j − 1      1
                 = t            D  s
                           s         t  K j−s
                    s=0
                    j−1
                         j − 1
                                    1
                 = t            D  s   D j−1−s (tC)
                           s         t
                    s=0
                 = tD (j−1) (C)
                 = tC (j−1) .
   108   109   110   111   112   113   114   115   116   117   118