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6.10 The Einstein and Ernst Equations  289

          Proof. Multiply the rth row of A by ω −r ,1 ≤ r ≤ n and the sth column
          by ω ,1 ≤ s ≤ n. The effect of these operations is to multiply A by the
              s
          factor 1 and to multiply the element a rs by ω  s−r . Hence, by (6.10.6), A is
          transformed into B and the lemma is proved.

            Unlike A, which is real, the cofactors of A are not all real. An example
          is given in the following lemma.
          Lemma 6.18.
                                               2
                             A 1n = ω n−1  B 1n  (ω = −1).
          Proof.

                                A 1n =(−1) n+1 |e rs | n−1 ,
          where


                                e rs = a r+1,s
                                   = ω  |r−s+1| u |r−s+1|
                                   = a r,s−1
          and
                                B 1n =(−1) n+1 |β rs | n−1 ,
          where

                                    β rs = b r+1,s
                                        = b r,s−1 ,

          that is,
                                   β rs = ω s−r−1 e rs .
                                (n)    −r−1
          Multiply the rth row of A  by ω  ,1 ≤ r ≤ n − 1 and the sth column
                                1n
                                                                     (n)
          by ω ,1 ≤ s ≤ n − 1. The effect of these operations is to multiply A  by
              s
                                                                     1n
          the factor
                         ω −(2+3+···+n)+(1+2+3+···+n−1)  = ω 1−n
          and to multiply the element e rs by ω s−r−1 . The lemma follows.
            Both A and B are persymmetric (Hankel) about their secondary diag-
          onals. However, A is also symmetric about its principal diagonal, whereas
          B is neither symmetric nor skew-symmetric about its principal diagonal.
          In the analysis which follows, advantage has been taken of the fact that A
          with its complex elements possesses a higher degree of symmetry than B
          with its real elements. The expected complicated analysis has been avoided
          by replacing B and its cofactors by A and its cofactors.
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