Page 308 - Determinants and Their Applications in Mathematical Physics
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6.10 The Einstein and Ernst Equations  293

          Proof. The proof is by induction and applies the B¨acklund transforma-
          tion theorems which appear in Appendix A.12 where it is proved that if
          P(φ, ψ) is a solution and
                                           φ

                                   φ =         ,
                                        φ + ψ 2
                                         2
                                            ψ

                                   ψ = −   2   2  ,                (6.10.15)
                                         φ + ψ
          then P (φ ,ψ ) is also a solution. Transformation β states that if P(φ, ψ)



          is a solution and
                                     ρ
                                φ =   ,

                                    φ
                              ∂ψ      ωρ ∂ψ
                                  = −       ,
                               ∂ρ     φ 2  ∂z
                              ∂ψ     ωρ ∂ψ    2
                                  =         (ω = −1),              (6.10.16)
                               ∂z    φ 2  ∂ρ
          then P (φ ,ψ ) is also a solution. The theorem can therefore be proved by



          showing that the application of transformation γ to P n gives P and that

                                                                 n
          the application of Transformation β to P gives P n+1 .

                                             n
            Applying the Jacobi identity (Section 3.6) to the cofactors of the corner
          elements of A,
                                A 2 n+1  − A 2 1n  = A n A n−2 .   (6.10.17)
          Hence, referring to (6.10.15),
                                          
 2
                                      ρ         2     2
                                    	  n−2
                           2
                                2
                          φ + ψ =             A n−1  − E n−1
                           n    n
                                     A n−2
                                          
 2
                                    	  n−2
                                      ρ         2     2
                                  =           A    − A
                                               n−1
                                     A n−2            1n
                                    ρ 2n−4
                                  =      A n ,                     (6.10.18)
                                     A n−2
                                     A n−1
                                  =           (A n−1 = A 11 )
                            φ n
                           2
                          φ + ψ 2   ρ 2n−2
                           n    n        A n
                                     A 11
                                  =
                                    ρ 2n−2

                                  = φ ,
                                     n
                                     ωE n−1
                                  =
                            ψ n
                           2
                          φ + ψ 2   ρ 2n−2
                           n    n        A n
                                    (−1) n−1 ωA 1n
                                  =
                                        ρ n−2

                                  = −ψ .
                                       n
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