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3.7 Bordered Determinants  47

          and let B n denote the determinant of order (n + 1) obtained by bordering
          A n by the column


                                                   T
                                X = x 1 x 2 x 3 ··· x n
          on the right, the row

                                 Y = y 1 y 2 y 3 ··· y n
          at the bottom and the element z in position (n +1,n + 1). In some detail,


                                 a 11  a 12  ···  a 1n  x 1

                                 a 21  a 22  ···  a 2n  x 2
                                                          .          (3.7.1)

                          B n =   ........................

                                 a n1  a n2  ··· a nn  x n
                                                    z
                                y 1  y 2  ···
                                                      n+1
                                              y n
          Some authors border on the left and at the top but this method displaces
          the element a ij to the position (i +1,j + 1), which is undesirable for both
          practical and aesthetic reasons except in a few special cases.
            In the theorems which follow, the notation is simplified by discarding the
          suffix n.
          Theorem 3.9.
                                        n   n

                              B = zA −        A rs x r y s .
                                       r=1 s=1
          Proof. The coefficient of y s in B is (−1) n+s+1 F, where

                          F = C 1 ... C s−1 C s+1 ... C n X

                                                         n
                            =(−1)  n+s G,
          where

                           G = C 1 ... C s−1 XC s+1 ... C n .


                                                        n
          The coefficient of x r in G is A rs . Hence, the coefficient of x r y s in B is
                              (−1) n+s+1+n+s A rs = −A rs .
          The only term independent of the x’s and y’s is zA. The theorem
          follows.

            Let E ij denote the determinant obtained from A by
          a. replacing a ij by z, i, j fixed,
          b. replacing a rj by x r ,1 ≤ r ≤ n, r  = i,
          c. replacing a is by y s ,1 ≤ s ≤ n, s  = j.
          Theorem 3.10.
                                      n   n

                         B ij = zA ij −     A ir,js x r y s = E ij .
                                     r=1 s=1
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