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0593_C04*_fm  Page 105  Monday, May 6, 2002  2:06 PM





                       Kinematics of a Rigid Body                                                  105



                                n
                                 x
                                                                                           1 rev/sec
                       n                                                     n
                         y      n                                      n      z
                                 z                                      x
                                                   25 ft
                                                                                   L
                                                                                                   W
                                             25 ft                   n  y                  O
                               15 mph    C
                                                                                        6 in


                       FIGURE 4.10.2                                FIGURE 4.10.3
                       Sports car C entering a turn to the right.   Sports car steering wheel W and left hand L.


                              *
                       where L  is that point of the car C where L is located at the instant of interest and where,
                                                                            L
                                                                          C
                       as before, S is the fixed road surface. From Figure 4.10.3,  V  is:
                                             V = ωω  × OL = 2π n × 0 433 n + 0 25 n
                                            C  L  C  W         x (             z)
                                                                   .
                                                                           .
                                                                        y
                                                                                              (4.10.13)
                                               =−1 571 n + 2 71 n ft sec
                                                            .
                                                   .
                                                        y      z
                       From Figure 4.10.2,  V  is:
                                        S
                                           L*
                                              V =  V + ωω  × OL
                                             S  L*  S  O  S  C
                                                             z ( 0
                                                 = 22 n + 0 .88 n ×  .433 n + 0 .25 n z)      (4.10.14)
                                                                       y
                                                      x
                                                 = 22 .381 n ft sec
                                                         x
                       Therefore, by substituting into Eq. (4.10.12), the velocity of L is:

                                             S  L
                                                                      .
                                                             .
                                              V = 22 381 n − 1 571 n + 2 71 n ft sec          (4.10.15)
                                                     .
                                                          x       y      z
                       In like manner, from Eq. (4.10.11), the acceleration of L is:
                                                    a =  a +  a +2 ωω  ×  V                   (4.10.16)
                                                   S  L  C L  S L*  S  C  C  L
                       From Figure 4.10.3,  a  is:
                                        C L
                                                              x [                       z)]
                                                                       x (
                                     L
                                       C
                                   C a = ωω W  ×( ωω W  ×  OL) = 6 238.  n × 6 283.  n × 0 433.  n + 0 25.  n
                                             C
                                                                                y
                                                                                              (4.10.17)
                                          .
                                      =−17 095 n − 9 87.  n ft sec 2
                                               y       z
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