Page 522 - Dynamics of Mechanical Systems
P. 522

0593_C14_fm  Page 503  Tuesday, May 7, 2002  6:56 AM





                       Stability                                                                   503


                       Note that in the development of these equations we have neglected all products of small
                                             *
                       quantities (those with a [ ]). Also, we have approximated trigonometric functions as:

                                              =
                                          sinθθ  * , cosθ = 1 , sinψ =− ψ  * , cosψ =−1       (14.6.70)
                       The last of these makes the sum (1 + cosψ) vanish, leading to the simple forms of Eqs.
                       (14.6.67), (14.6.68), and (14.6.69).
                        After further simplification, we see that Eqs. (14.6.67) and (14.6.68) may be written in
                       the forms:

                                                      a θ +  a ψ +  ˆ a θ =  0                (14.6.71)
                                                                   *
                                                      ˆ ˙˙ *
                                                           ˆ ˙ *
                                                       1
                                                            2
                                                                 3
                       and
                                                                 ˆ
                                                      ˆ
                                                     b ψ +  b θ +  b ψ =  0                   (14.6.72)
                                                                   *
                                                           ˆ ˙ *
                                                       ˙˙ *
                                                      1     2    3
                       where the a  and b  (i = 1, 2, 3) are:
                                       i
                                 i
                                              ˆ a =  5 , a = − 6φ ˙  , a = −( 4 g r) −  5φ ˙ 2
                                                     ˆ
                                                                ˆ
                                               1      2     0   3             0
                       and
                                                       ˆ
                                                                ˆ
                                                ˆ
                                                b =  3 , b = 5φ ˙  , b = ( 2 mg Mr)           (14.6.73)
                                                 1      2    0   3
                        Following the procedure of the foregoing case we can solve Eqs. (14.6.67) and (14.6.68)
                                 *
                       by letting θ  and ψ  have the forms:
                                       *
                                                        *
                                                    *
                                                  θ = Θ e  λt  and  ψ = Ψ e  λt               (14.6.74)
                                                                        *
                                                                   *
                       Then, Eqs. (14.6.67) and (14.6.68) become:
                                                 ˆ a λ Θ * λ t  ˆ a λΨ * λ t  ˆ a Θ * λ t  0  (14.6.75)
                                                                       e =
                                                               e +
                                                      e +
                                                   2
                                                  1        2        3
                       and
                                                          ˆ
                                                                   ˆ
                                                 ˆ
                                                 b λ Ψ * λ t  b λΘ * λ t  b Ψ * λ t  0        (14.6.76)
                                                               e +
                                                      e +
                                                                       e =
                                                   2
                                                  1        2        3
                       or
                                                    (  ˆ a λ + )Θ * +  ˆ a λΨ  *  =  0        (14.6.77)
                                                       2
                                                          ˆ a
                                                                 2
                                                           3
                                                      1
                       and
                                                    b λΘ + ( b λ + )  *
                                                            ˆ
                                                    ˆ
                                                                 ˆ
                                                                 b Ψ =
                                                              2
                                                        *
                                                     2       1    3    0                      (14.6.78)
   517   518   519   520   521   522   523   524   525   526   527