Page 518 - Dynamics of Mechanical Systems
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0593_C14_fm  Page 499  Tuesday, May 7, 2002  6:56 AM





                       Stability                                                                   499


                                                            *
                       where, as before, the quantities with the ( ) are small. Then, Eqs. (14.6.28), (14.6.29), and
                       (14.6.30) become (after simplification):
                                         ( Mr +  I 4 mr )θ  +− (  Mr −  I − 6 mr )φ ψ
                                                               2
                                             2
                                                                         2 ˙ ˙ *
                                                     2 ˙˙*
                                                                            0
                                                11
                                                                  22
                                                                             0]
                                           [
                                                                          2 ˙
                                                 −
                                         +−  Mgr 2 mgr −( Mr + I −  I +  4 mr )φθ *  =  0     (14.3.37)
                                                                             2
                                                            2
                                                               22
                                                                   33
                                           ( Mr + I +  4 mr )ψ  +( 2 Mr +  I + 8 mr )φ θ
                                                         2
                                              2
                                                                   2
                                                                             2 ˙ ˙ *
                                                          ˙˙ *
                                                                      22
                                                  22
                                                                               0
                                           −(  mr φ  + mgr)ψ *  =                             (14.6.38)
                                                2 2 ˙
                                             2
                                                  0          0
                       and
                                                            ˙˙*
                                                            φ= 0                              (14.6.39)
                        To solve these equations, let I  = I  = (1/2)I  = (1/4)Mr , and let Eqs. (14.6.37) and
                                                                             2
                                                    11
                                                        33
                                                                  22
                       (14.6.38) be written in the forms:
                                                            ψ +
                                                      a θ +  a ˙ *  a θ =  0                  (14.6.40)
                                                       ˙˙*
                                                                   *
                                                      1     2     3
                       and
                                                       ψ +
                                                                   *
                                                             ˙ *
                                                     b ˙˙ *  b θ +  b ψ =  0                  (14.6.41)
                                                      1     2    3
                       where the coefficients a  and b  (i = 1, 2, 3) are:
                                                 i
                                            i
                                         a = ( 45) Mr +   2  a = − ( [  3 2) Mr +  mr φ 0 ]
                                                                                2 ˙
                                                    2
                                                                          2
                                          1            4 mr ,  2            6
                                                   −
                                                                        2 ˙
                                         a =− Mgr 2  mgr − ( [  5 4) Mr +  4 mr φ 0 ]  2
                                                                  2
                                          3
                                         b = ( 32) Mr +   2  b = ( [  5 2) Mr +  mr φ 0 ]     (14.6.42)
                                                                               2 ˙
                                                    2
                                                                        2
                                          1            4 mr ,  2           8
                                                          2 ˙
                                         b =− mr ( [  g r) + 2φ 0]
                                                 2
                                          3
                       Observe that the signs of these coefficients are:
                                                    a >  0,  a <  0,  a <  0
                                                     1       2       3
                                                                                              (14.6.43)
                                                    b >  0,  b >  0,  b <  0
                                                     1       2       3
                       Observe further that the a  and b  (i = 1, 2, 3) may be written in the forms:
                                              i
                                                    i
                                              a = ,    a =− φ ˙  ,  a =− c − φ 2 ˙
                                                  c
                                                                           c
                                                            c
                                               1   1    2    2 0   3    3   4 0
                                                                                              (14.6.44)
                                              b =  c ,  b = φ ˙    b =− c − φ 2 ˙
                                               1   5    2  c 6 0  ,  3  7  c 8 0
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