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190   Electric Drives and Electromechanical Systems


























             FIG. 7.2 Equivalent circuit of an induction motor. (A) A transformer per phase model of the induction motor. (B)
             Induction motor model where all rotor components are referred to the stator.

             lags the voltage by the rotor power factor, q r . The phasor diagram for the motor whose
             equivalent circuit is shown in Fig. 7.2B is given in Fig. 7.3. The derivation of the electrical
             torque as a function of the rotor current and the flux is somewhat complex; this
             derivation is fully discussed in the literature (Bose, 2006). The torque can be expressed in
             the form


                                             T e ¼ K T j j m j I r sin d                  (7.4)
                                                        b
             where K T is the effective induction-motor torque constant, jj m j is the peak air-gap flux,

              I r is the peak value rotor current, and d ¼ 90 þ q r . The torque constant, K T , is dependent
              b
             on the number of poles and on the motor’s winding configurations.
                At a standstill, when the motor’s slip is equal to unity, the equivalent circuit
             corresponds to a short-circuited transformer; while at synchronous speed, the slip, and
             hence the rotor current, is zero, and the motor supply current equals the stator’s
             excitation current, I 0 . At sub-synchronous speeds, with the slip close to zero, the rotor
             current is principally influenced by the ratio R r /s.
                From this equivalent circuit of the induction motor, the following relationships apply,
                                         Input power ¼ P i ¼ 3V s I s cos f              (7.5a)

                                                           2
                                                         3I R r ð1   sÞ
                                                           r
                                       Output power ¼ P o ¼                              (7.5b)
                                                              s
                Since the rotational output power is the product of the speed and the torque, the
             generated torque can be expressed as,
                                                   2           2
                                            P o  3 I R r ð1   sÞ  3I R r p
                                                               r
                                                   r
                                        T e ¼  ¼            ¼                             (7.6)
                                            u r      su r      su s
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