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2
                                                                                              2
                                                                                                   2
                                                                                    2
                        Figure 4.28: Propagation behavior of the angular spectrum for (a) k ≤ k ,(b) k > k .
                                                                                    x         x
                        is determined by the values of the field over the boundaries of the solution region. But
                        this is not the whole picture. The inverse transform integral also requires values of k x in
                                                                   2
                                                                       2
                        the intervals [−∞, k] and [k, ∞]. Here we have k > k and thus
                                                                   x
                                                                    √
                                                                         2
                                                                       2
                                                 e − jk x x − jk y y  = e  − jk x x ∓  k x −k y ,
                                                                  e
                                                      e
                        where we choose the upper sign for y > 0 and the lower sign for y < 0 to ensure
                        that the field decays along the y-direction. In these regimes we have an evanescent wave,
                        propagating along x but decaying along y, with surfaces of constant phase and amplitude
                        mutually perpendicular (Figure 4.28). As k x ranges out to ∞, evanescent waves of all
                        possible decay constants also contribute to the plane-wave superposition.
                          We may summarize the plane-wave contributions by letting k = ˆ xk x + ˆ yk y = k r + jk i
                        where

                                                              2   2    2   2
                                                     ˆ xk x ± ˆ y k − k ,  k < k ,
                                                                  x
                                                                       x
                                               k r =
                                                                           2
                                                                       2
                                                     ˆ xk x ,         k > k ,
                                                                       x
                                                                   2   2
                                                     0,           k < k ,
                                                                   x
                                               k i =
                                                                   2
                                                                       2
                                                          2
                                                              2
                                                     ∓ˆ y k − k ,  k > k ,
                                                          x        x
                        where the upper sign is used for y > 0 and the lower sign for y < 0.
                          In many applications, including the half-plane example considered later, it is useful to
                        write the inversion integral in polar coordinates. Letting
                                                 k x = k cos ξ,  k y =±k sin ξ,
                        where ξ = ξ r + jξ i is a new complex variable, we have k · ρ = kx cos ξ ± ky sin ξ and
                        dk x =−k sin ξ dξ. With this change of variables (4.401) becomes
                                                  k
                                      ˜                           − jkx cos ξ ± jky sin ξ
                                     ψ(x, y,ω) =       A(k cos ξ, ω)e   e       sin ξ dξ.     (4.402)
                                                 2π  C
                        Since A(k x ,ω) is a function to be determined, we may introduce a new function
                                                            k
                                                   f (ξ, ω) =  A(k x ,ω) sin ξ
                                                            2π
                        © 2001 by CRC Press LLC
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