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Sec. 5.4   Differential Reactors                               247

                                  The exit volumetric flow rate from a differential packed bed containing 10 g of cat-
                                   alyst was maintained at 300 dm3/min for each run. The partial pressures of  €€,  and
                                   COI were determined at the entrance to the reactor, and the methane concentration
                                   was measured at the reactor exit.

                                   Solution
                                   (a) In this example the product composition, rather than the reactant concentration,
                                   is being monitored. -rA  can be written in terms of  the flow rate of  methane from
                                   the reaction,




                                   Substituting fiar FcH4 in terms of the volumetric flow rate and the concentration of
                                   methane gives

                                                                                             (E5-4.3)

                                   Since uo, CCHb, and AW are known for each run, we can calculate the rate of reaction.
                                        For run  1:
                                                                g moudm3 = 7.33 x 10-3  g mol CH,
                                                                                    g cat. X min
                                   The rate for runs 2 through 6 can be calculated in a similar manner (Table E5-4.2).

                                                   TABLE E5-4.2.   RAW AND  CALCULATED DATA
                                                                                               -




                                                                                            ~
                                        1      1 .o       1 .o      2.44 x 10-4     7.33 x 10-3
                                        2      1.8        1 .o      4.40 x 10-4     13.2 x 10-3
                                        3      4.08       1 .o      10.0 x 10-4     30.0 x IO-j
                                        4      1.0        0.1       1.65 x 10-4     4.95 x IO-’
                                        5      1 .o       0.5       2.47 x 10-4     7.42 X  lo-’
                                        6      1 .o       4.0       1.75 x 10-4     5.25  X  IO-j


                                   For constant hydrogen concentration, the rate law

                                                           IbH,  = kG0 * @H,)
                                   can be written as
                                           -*                 rkH4 = k‘ Pso                  (E5-4.4)

                                   Taking the log of Equation (E5-4.4) gives us
                                                         In(rkH4) = lnk‘+a InPC,

                                   We now plot In (r&) versus In Pco  for runs 1, 2, and 3.
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