Page 288 - Elements of Chemical Reaction Engineering 3rd Edition
P. 288

260                            Collection  and Analysis of  Rate Data   Chap. 5









         Note that  the error is
            not  ;I functictn  of                                      0
           rite ;tnd  appearh  lo           t  O
               be  zindoirily         -0.050  1
                distributed
                                      -O.l0@ j-                       0


                                      -0.15U -+---+--+-----~~                        RATE
                                           0.500   1.500   2.500   3.500   4.500   5.500



                                error  =  RFiTE  -  (itPe*PH2,'1"YexPe))
                                1  =  3.18678
                                Ke  =  2.13133
                                         Figure  E5-6.1  F.iior  as  d  lunct~on of calculated rate.


                               However.  there  is  a  caution!  One  cannot  simply carry  out  a  regression
                          and then  pick  the  model  with  the  lowest value of  the sums of  squares. If  this
                          were  the  case,  we  would  have  chosen  model  (a) with  u2 = 0.03. One must
                          consider the physical  realism of  the  parameters. In  model  (a) the 95% confr-
                          dence interval was greater than the parameter itself, thereby  yielding negative
                          values of the parameter,  Kti, which  is physically  impossible.
                              We can  also use  nonlinear regression  to  determine the rate  law parame-
                          ters  from  concentration-time  data  obtained  in  batch  experiments.  We  recall
                          that  the  combined  rate  law-stoichiometry-mole balance  for a constant-volume
                          batch reactor is






                          We now integrate  Equation  (5-6) to give

                                                        I
                                                  I
                                                C,4,, - C,,   LV   = (1 - CX) kt
                                                   li
                          Rearranging to obtain the concentration as  ii  function of time, we obtain
                                              c, = { ck,;"- (1 - CX)kt]''I-a           (5-36)

                          Now we could use POLYMATH or MATLAB to find the values of  CY  and k that
                          would  minimize the  sum of  squares of  the differences between  the measured
                          and calculated  concentrations. That is, for N  data points,
   283   284   285   286   287   288   289   290   291   292   293