Page 340 - Elements of Distribution Theory
P. 340

P1: JZP
            052184472Xc11  CUNY148/Severini  May 24, 2005  17:56





                            326                 Approximation of Probability Distributions

                            Case 1: Suppose that there exists a constant M such that, with probability 1,

                                                     |X n |≤ M,  n = 1, 2,...
                            and |X|≤ M. We may assume, without loss of generality, that M is a continuity point of F.
                              Consider a bounded, continuous, function f : R → R and let  > 0. Let x 1 , x 2 ,..., x m
                            denote continuity points of F such that

                                            −M = x 0 < x 1 < ··· < x m−1 < x m < x m+1 = M
                            and

                                                  max    sup  | f (x) − f (x i )|≤  .
                                                  1≤i≤m x i ≤x≤x i+1
                            Define

                                                 f m (x) = f (x i )  for x i ≤ x < x i+1 .
                            Then, as n →∞,
                                             M                m


                                                f m (x) dF n (x) =  f (x i )[F n (x i+1 ) − F n (x i )]
                                            −M               i=1
                                                              m

                                                           →     f (x i )[F(x i+1 ) − F(x i )]
                                                              i=1
                                                                M
                                                           =     f m (x) dF(x).
                                                              −M
                              Hence, for sufficiently large n,

                                                     M

                                                       f m (x)[dF n (x) − dF(x)]  ≤  .


                                                   −M
                            It follows that
                                    M


                                      f (x)[dF n (x) − dF(x)]
                                  −M
                                        M                                 M


                                  ≤     [ f (x) − f m (x)][dF n (x) − dF(x)]  +    f m (x)[dF n (x) − dF(x)]
                                      −M                                −M
                                  ≤ 3 .
                            Since   is arbitrary, it follows that
                                                     lim E[ f (X n )] = E[ f (X)].
                                                     n→∞
                            Case 2: For the general case in which the X 1 , X 2 ,... and X are not necessarily bounded,
                            let 0 <  < 1be arbitrary and let M and −M denote continuity points of F such that

                                                  M
                                                   dF(x) = F(M) − F(−M) ≥ 1 −  .
                                                −M
                            Since

                                          F n (M) − F n (−M) → F(M) − F(−M)as n →∞,
   335   336   337   338   339   340   341   342   343   344   345