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                                        11.2 Basic Properties of Convergence in Distribution  327

                        it follows that
                                            M

                                              dF n (x) = F n (M) − F n (−M) ≥ 1 − 2
                                           −M
                        for sufficiently large n. Hence,
                                                           M
                               ∞

                                                            f (x)[dF n (x) − dF(x)]  + sup | f (x)|3 .

                                 f (x)[dF n (x) − dF(x)]  ≤
                              −∞                         −M                       x
                        The same argument used in case 1 can be used to shown that
                                            M

                                             f (x)[dF n (x) − dF(x)]  → 0as n →∞;


                                          −M
                        since   is arbitrary, it follows that
                                                 ∞


                                                   f (x)[dF n (x) − dF(x)]  → 0


                                                −∞
                        as n →∞, proving the first part of the theorem.
                          Now suppose that E[ f (X n )] converges to E[ f (X)] for all real-valued, bounded, contin-
                        uous f . Define
                                                       1      if x < 0

                                               h(x) =  1 − x  if 0 ≤ x ≤ 1
                                                       0      if x > 1
                        and for any t > 0 define h t (x) = h(tx).
                          Note that, for fixed t, h t is a real-valued, bounded, continuous function. Hence, for all
                        t > 0,
                                                 lim E[h t (X n )] = E[h t (X)].
                                                 n→∞
                          For fixed x,


                                               I {u≤x} ≤ h t (u − x) ≤ I {u≤x+1/t}
                        for all u, t. Hence,
                                                 ∞

                                        F n (x) ≤  h t (u − x) dF n (u) = E[h t (X n − x)]
                                                −∞
                        and, for any value of t > 0,
                                 lim sup F n (x) ≤ lim E[h t (X n − x)] = E[h t (X − x)] ≤ F(x + 1/t).
                                              n→∞
                                  n→∞
                        It follows that, if F is continuous at x,
                                                   lim sup F n (x) ≤ F(x).                 (11.1)
                                                    n→∞
                          Similarly, for fixed x,

                                             I {u≤x−1/t} ≤ h t (u − x + 1/t) ≤ I {u≤x}
                        for all u, t > 0. Hence,
                                            ∞

                                   F n (x) ≥  h t (u − x + 1/t) dF n (u) = E[h t (X n − x + 1/t)]
                                           −∞
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