Page 493 - Elements of Chemical Reaction Engineering Ebook
P. 493

464                       Steady-State Nonisothermal Reactor Design   Chap. 8

                                      Because only A enters,
                                                      EO, cpi = cp,

                                 and Equation (E8-7.7) becomes











                             dT
                             -
                             dV
             Adiabatic PFR    6.  Calculation of mole balance parameters:
           with variable heat
                 capacities                kg/h  = 137.9 kmol/h = 38.3  mol/s
                                     = 58 g/mol
                                 CA, = -          162 Ha       = 0.0188 - 18.8 m0l/m3
                                                                      kmol  -
                                       ‘A0
                                          =
                                                                           -
                                       RT                              m3
                                            8.3 1      (1035 K)
                                                hol* K
                                       FAO  -
                                  uo = - - 2.037 m3/s
                                       CAO
                              7.  Calculation of energy balance parameters:
                                 a.  AHix (TR): At 298 K, the standard heats of formation are
                                          H;x(TR)acetone -216.67 kJ/mol
                                                    =
                                          Hix(TR)ketene -61.09 kJ/mol
                                                    =
                                         Hix(TR)me*me = -74.81 kJ/mol
                                            AHiX(TR) = (-61.09) + (-74.81) - -216.67)
                                                                         (
                                                    = 80.77 kJ/mol
                                 b.  ACp: The heat capacities are:
                                    CH3COCH3:  C,,  = 26.63 + 0.1837‘-  45.86 X 10-6T2 J/mol..K
                                    CH,CO:     C,,  = 20.04 + 0.0945T - 30.95 X   T2 J/mol* K
                                    CH, :      Cpc = 13.39+0.077T-  18.71 x 10-6T2 J/mol-K

                                Aa = aC + a, - aA = 13.39 + 20.04 - 26.63
                                   = 6.8 J/mol-K
                                AP = Pc + PB - PA = 0.077 + 0,0945 - 0.1 83
                                   = -0.0115 J/mol.K2
                                Ay  = yc+yB-yA = (-18.71 X 10-6)+(-30.95X  10-6)-(-45.86X

                                   = - 3.8 X   J/mol. K3
   488   489   490   491   492   493   494   495   496   497   498