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Sec. 9.2   Unsteady Operation of  CSTRs and Semibatch Reactors   539

                                    4.  Combining Equations (E9-l.l), (E9-1.2), and (2-6), we have

                                                            dx -- - k(l - X)               (E9-1.3)
                                                            dt
                                      From the data in Example 8-4,

                                                  k = (4.71 X  IO9) exp

                                      or


                                                                                           (E9-1.4)
                                      A table similar to that used in Example 8-6 can now be constructed.
                                    5.  Energy balance. Using Equation (9-17), the relationship between X and T for
                                      an adiabatic reaction is given by

                                                                                           (E9- 1.5)

                                    6.  Evaluating the parameters in the energy balance gives us the heat capacity
                                      of  the soliution:

                                           cPs = c O, Cp, = @AZlpA + oBC,B  + oCZ;C  + o,C,I
                                             = (1)(35) + (18.65)(18) + 0 + (1.670)(19.5)
                                             = 403 Btu/lb mol A."F
                                      From Example 8-4, AeP = -7 Btu/lb mol-"F and consequently, the second
                                      term on the right-hand side of  the expression folr the heat of  reaction,
                                                AHRx(T) = AH;;,(TR)+A6p(T-~R)
                                                        = -36,400 - 7(T - 528)             (E8-4.7)
                                      is very small compared with the first term [less than 2%  at 51.5% conversion
                                       (from Example 8-4)].
                                           Taking the heat of  reaction at the initial temperature of 535"R,
                                                AHR~(T,) = -36,400 - (7)(535 - 528)
                                                        = -36,450 Btu/lb mol
                                           Because terms containing Atp are very small, it can be assumed that
                                                              Aep = 0
                                      In  calculating the  initial temperature, we  must  include the temperature rise
                                       from the heat of mixing the two solutions:

                                             & = (460 + 58) + 17
                                               = 535"R




                                               = 535 + 90.45 X                             (E9- 1.6)
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