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Sec. 9.2   Unsteady Operation of CSTRs and Semibatch Reactors   543

                  A management      2.  The reaction is normally carried out isothermally at 175°C over a 24-h period.
                decision was made      Approximately  45  min  after  the  reaction  was  started,  cooling  to  the  reactor
                to triple production   was halted, but only for  10 min. Cooling may have been halted for 10 min or
                                       so on previous occasions when the normal charge of 3.17 kmol of ONCB was
                                       used and no ill effects occurred.
                                       The reactor had a safety relief valve whose disk would rupture when the pres-
                                  sure  exceeded  approximately  700  psi.  Once  the  disk  ruptures,  the  water  would
                                  vaporize,  and i.he  reaction  would be cooled (quenched)  by  the release of  the latent
                                  heat of  vaporization.
                                       Plot the temperature-time trajectory up to a period of  120 min after the reac-
                                  tants were mixed and brought up to 175°C. Show that the following three conditions
                                  had  to  have been  present  for the explosion  to occur:  (1) increased  ONCB  charge,
                                  (2) reactor  stopped for  10 min, and (3) relief  system failure.

                                  Additional Information: The rate law is

                                                             with  k  = 0.00017   m3   at 188°C
                                                                            kmol * min
                                  The reaction volume for the charge of  9.044 kmol of  ONCB:
                                             V = 3.265 m3 ONCB/NH3 + 1.854 m3 II,O  = 5.119 m3

                                  The reaction volume for the charge of  3.17 kmol of ONCB:
                                             V  = 3.26 m3
                                         AH,,  = -5.9 X IO5 kcallkg mol
                                            E  = 11,273 cal/mol
                                        CpONCB CPA = 40 cal/mol. K
                                              =
                                         CPHZo = Cpw = 18 cal/mol.K   CNHl = CPB = 8.38 cal/mol.K
                                  Assume that  Akp=O :






                                  Solution
                                                         A+2B  __j C+D
                                  Mole balance:


                                                                                            (E9-2.1)

                                  Rate law:
                                                             -rA  = kC,C,                   (E9-2.2)
                                  Stoichiometry (liquid phase):
                                                            CA  = cAO(1 -x)                 (E9--2.3)
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