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              Optical Fiber Techniques for Medical Applications                                           317























                                                                FIGURE 2 Trajectory of a ray in a cylindrical rod. (a) A rod of
              FIGURE 1 Reflection and refraction at the interface between two  refractive index n 1 in air (n 0 = 1). (b) A rod whose core has a
              media of refractive indices n 1 and n 2 (n 1 > n 2 ). (a) Incident angle  refractive index n 1 and cladding index n 2 (n 2 < n 1 ).
              θ 1 <θ c . (b) Incident angle θ 1 = θ c . (c) Incident angle θ 1 >θ c ; total
              internal reflection.
                                                                face  of  the  rod  are  shown  in  Fig.  2(a).  Ray  II  will  be
              A. Properties of Optical Fibers                   refracted inside the rod and refracted back in air. Ray I,
                                                                on the other hand, will be totally internally reflected
                1. Total lnternal Reflection                     inside the rod and will emerge from the second face of
                                                                the rod. This will also happen when the rod is very thin
              Consider two transparent media of refractive indices n 1
                                                                and flexible, and in this case the rod is called an optical
              and n 2 , where n 1  > n 2  (Fig. 1). A ray of light propagates
                                                                fiber. A fiber consisting of a transparent material in air
              at an angle θ 1 with respect to the normal to the inter-
                                                                is called an unclad fiber. Light will propagate inside the
              face between the media. At the interface, part of the beam
                                                                rod (or fiber) by a series of internal reflections, even if
              will be reflected back to medium 1, and part will be re-
                                                                the rod is not in air, as long as n 2 < n 1 . In particular, a
              fracted into medium 2. The reflection is specular (the an-
                                                                compound rod may consist of the inner part of index
              gle of reflection is equal to the angle of incidence θ 1 ).
                                                                n 1 , called core, and the outer part of index n 2 , called
              The refraction obeys Snell’s law as shown in Fig. 1(a),
                                                                cladding. If this rod is thin, the optical fiber formed is
              so that n 1 sin θ 1 = n 2 sin θ 2 . If the angle θ 1 is increased,
                                                                called a clad fiber. The cross section of the rod (or the
              one may reach some angle θ 1 = θ 1c , for which θ 2 = 90 .
                                                          ◦
                                                                fiber)  is  shown  in  Fig.  2(b),  with  the  trajectory  of  an
              Here θ 1c is called the critical angle, and for this angle we
                                                                incident ray of light. Assume that the angle of incidence
                                    ◦
              write n 1 sin θ 1c = n 2 sin 90 = n 2 . For every angle of in-
                                                                in air is α 0 and that inside the core the beam is refracted
              cidence θ 1 >θ 1c , there is no refracted beam. Were there
              such a beam, its angle θ 2 would be given by the equation:  at an angle α 1 , as shown. We can write n 0 sin α 0 =
                                                                                              1/2
                                                                                          2
                                                                n 1 sin α 1 = n 1 cos θ 1 = n 1 (1 − sin θ 1 )  , where n 0 = 1is
              sin θ 2 = (n 1 sin θ 1 )/n 2 > (n 1 sin θ 1c )/n 2 = 1. Since this of
                                                                the refractive index in air. The angle θ 1 can assume sev
              course is impossible, there is only a reflected beam. This
                                                                eral values, but its maximum value for total internal reflec-
              phenomenon,  shown  in  Fig.  1(c),  is  called  total  inter-
                                                                tion is the critical value θ 1c , given by n 1 sin θ 1c =−n 2 .We
              nal reflection. If medium 1 is glass with n 1 = 1.5 and
              medium 2 is air with n 2 = 1, the critical angle is given  can calculate α 0max , the value of α 0 corresponding
                                                                                                         1/2
                                                                                                     2
              by sin θ 1c = 1/1.5. In this case, θ 1c = 42 . If medium 2 is  to this value of θ: n 0 sin α 0max = n 1 (1 − sin θ 1c )  =
                                              ◦
                                                                      2 1/2
                                                                  2
              soda-lime glass with n 2 = 1.52 and medium 1 is flint glass  (n − n )  . This value of n 0 sin α 0max is defined as the
                                                                  1
                                                                      2
                                                                                                           2
                                                                          aperture
              with n 1 = 1.67, then θ 1c = 65 . It should be mentioned that  numerical  1/2  NA:  NA = n 0 sin α 0max = (n −
                                    ◦
                                                                                                           1
                                                                 2 1/2
              in practice the total internal reflection is very efficient. In  n )  · (2	)  , where 	 = (n 1 − n 2 )/n 1 . Rays of light
                                                                 2
                                                                impinging on the surface at any angle α 0 <α 0max will
              this process more than 0.99999 of the incident energy is
                                                                be transmitted through the rod (or the optical fiber). All
              reflected, compared to about 0.95 for good metal mirrors.
                                                                these rays form a cone of angle α 0max . For angles of
                                                                incidence α 0 >α 0max , the ray will be refracted into the
                2. Optical Fibers
                                                                cladding and then into the air. The cone of light rays that
              Consider a rod of transparent material of refractive index  could be transmitted by the fiber is a measure for the
              n 1 in air (n 0 = 1). Two rays of light incident on one end  light-gathering capability of the fiber. The angle of the
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