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410                ENGINEERING ELECTROMAGNETICS

                                     where we have let jk 1 = 0 + jβ 1 in the perfect dielectric. These terms may be
                                     combined and simplified,

                                                           E xs1 = (e − jβ 1 z  − e jβ 1 z ) E x10
                                                                                +
                                                               =− j2 sin(β 1 z) E  +                 (11)
                                                                              x10
                                     Multiplying (11) by e  jωt  and taking the real part, we obtain the real instantaneous
                                     form:
                                                         E x1 (z, t) = 2E x10  sin(β 1 z) sin(ωt)    (12)
                                                                     +
                                     We recognize this total field in region 1 as a standing wave, obtained by combining
                                     two waves of equal amplitude traveling in opposite directions. We first encountered
                                     standing waves in transmission lines, but in the form of counterpropagating voltage
                                     waves (see Example 10.1).
                                        Again, we compare the form of (12) to that of the incident wave,

                                                          E x1 (z, t) = E  +  cos(ωt − β 1 z)        (13)
                                                                     x10
                                     Here we see the term ωt − β 1 z or ω(t − z/ν p1 ), which characterizes a wave traveling
                                     in the +z direction at a velocity ν p1 = ω/β 1 .In (12), however, the factors involving
                                     time and distance are separate trigonometric terms. Whenever ωt = mπ, E x1 is zero
                                     at all positions. On the other hand, spatial nulls in the standing wave pattern occur
                                     for all times wherever β 1 z = mπ, which in turn occurs when m = (0, ±1, ±2,...).
                                     In such cases,
                                                                  2π
                                                                     z = mπ
                                                                  λ 1
                                     and the null locations occur at

                                                                        λ 1
                                                                   z = m
                                                                        2
                                     Thus E x1 = 0at the boundary z = 0 and at every half-wavelength from the boundary
                                     in region 1, z < 0, as illustrated in Figure 12.2.
                                        Because E xs1  = η 1 H  +  and E  −  =−η 1 H ys1 , the magnetic field is
                                                                            −
                                                 +
                                                                 xs1
                                                          ys1
                                                                 E  +
                                                           H ys1 =  x10  (e − jβ 1 z  + e  jβ 1 z )
                                                                  η 1
                                     or
                                                                   E  +
                                                        H y1 (z, t) = 2  x10  cos(β 1 z) cos(ωt)     (14)
                                                                    η 1
                                     This is also a standing wave, but it shows a maximum amplitude at the positions
                                     where E x1 = 0. It is also 90 out of time phase with E x1 everywhere. As a result, the
                                                           ◦
                                     average power as determined through the Poynting vector [Eq. (77), Chapter 11] is
                                     zero in the forward and backward directions.
                                        Let us now consider perfect dielectrics in both regions 1 and 2; η 1 and η 2 are
                                     both real positive quantities and α 1 = α 2 = 0. Equation (9) enables us to calculate
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