Page 57 - Entrophy Analysis in Thermal Engineering Systems
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The common source of entropy increase                         49


              the air gained heat, whereas the pipe and the second tank lost heat. Inter-
              esting to note is that the heat gained was almost equal to the total heat lost.
              To correctly determine entropy generation, one would need to account for
              the heat transfer processes taking place between the different parts of the
              apparatus and the calorimeters.
                 Consider now a rigid tank, which, as before, contains a compressed ideal
              gas. It is then allowed to escape to the atmosphere. An expansion like this
              with air as the gaseous medium was also experimented by Joule [4]. The
              escaping air passed through a long coil of pipe in order to reduce the tem-
              perature of the air to its initial temperature. The entire assembly was placed
              in a water calorimeter. Joule’s observation was that heat was given off to the
              expanding air yielding a cooling effect in the calorimeter. These experiments
              led Joule to determine the mechanical equivalent of heat. The external work
              performed by the escaping air to overcome the atmospheric pressure was
              found to be the same as the amount of heat absorbed by the air. The ana-
              lytical formulation of Joule’s experiment was presented by Thomson [5] and
              later Clausius [6]. They both concluded that in the expansion process of air
              (treated as an ideal gas), it is necessary to supply heat to maintain a constant
              temperature. From these arguments, it should be obvious now that the
              entropy increase associated with the isothermal expansion of an ideal gas
              is indeed due to the heat transferred to the gas from an external source.
                 For an infinitesimal amount of work done in the expansion of an ideal
              gas, we have δQ¼δW, where δQ denotes the infinitesimal amount of heat
              supplied to maintain an isothermal expansion of the gas. Substituting
              δQ¼TdS and δW¼pdV gives

                                                                         (4.12)
                                         TdS ¼ pdV
              Integrating Eq. (4.12) from an initial volume to a final volume with the use
              of the ideal gas equation, one obtains


                                      ΔS ¼ nR ln  V f                    (4.13)
                                                  V i
              where ΔS is the increase in the entropy of the expanding gas.
                 Assume that the total heat Q required in the expansion process is supplied
              from a source whose temperature during the infinitesimal heat transfer δQ is
              T s . The net decrease in the entropy of the source is

                                                ð
                                                 δQ
                                        ΔS s ¼   T s                     (4.14)
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