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book   Mobk070    March 22, 2007  11:7








                     90  ESSENTIALS OF APPLIED MATHEMATICS FOR SCIENTISTS AND ENGINEERS
                       or, with

                                                           c

                                             g c (n α, x) =  f (ς)cos[n α(ς − x)]dς                 (5.91)
                                                         ς=0
                       we have
                                                            ∞

                                                     f (x) =   g c (n α, x) α                       (5.92)
                                                            n=1
                       As c approaches infinity we can imagine that  α approaches dα and n α approaches α,
                       whereupon the equation for f (x) becomes an integral expression

                                                       ∞   ∞
                                                    2
                                             f (x) =         f (ς)cos[α(ς − x)]dς dα                (5.93)
                                                    π
                                                      ς=0 α=0
                       which can alternatively be written as

                                                     ∞

                                             f (x) =   [A(α)cos α x + B(α)sin α x]dα                (5.94)
                                                   α=0
                       where
                                                              ∞
                                                           2
                                                   A(α) =       f (ς)cos ας dς                      (5.95)
                                                          π
                                                            ς=0
                       and

                                                              ∞
                                                           2

                                                   B(α) =       f (ς)sin ας dς                      (5.96)
                                                           π
                                                            ς=0
                       Example 5.8 (Transient conduction in a semi-infinite region). Consider the boundary value
                       problem

                                                    u t = u xx  (x ≥ 0, t ≥ 0)
                                                    u(0, t) = 0                                     (5.97)

                                                    u(x, 0) = f (x)

                       This represents transient heat conduction with an initial temperature f (x) and the boundary
                       at x = 0 suddenly reduced to zero. Separation of variables as T(t)X(x) would normally yield a
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