Page 199 - Essentials of physical chemistry
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More Kinetics and Some Mechanisms                                           161

            GRAPHICAL–ANALYTICAL METHOD FOR DH AND DS             z
                                                         z
            The method above is useful for estimating the Eyring parameters using only two data points in a test
            situation (hint), but for research we would want to use all the available data. In Figure 8.3, we plot
            the natural logarithms of the rate constants versus [1=T(K)] and get a very good fit to a straight line
            just as we did for the Arrhenius plot but here we will analyze the data in a different way (it is the
            same plot).
              Here, we can develop some useful relationships using the slope of the graph and the fact that
            DG ¼ DH   TDS . Let us start with the definition of the Eyring rate constant:
               z
                           z
                     z

                                        k B T     DS z      DH z     k B T  DG z
                                              e þ  R  e    RT     e    RT ,
                                K rate ¼                  ¼
                                         h                    h
            so then

                                              k B T    DS z    DH  z
                                  ln (K rate ) ¼ ln  þ              :
                                               h        R       RT
            To compare with the slope of the graph, we need


                                               k B  dT

                                                     1
                                   d ln (K rate )  h  d       DH  z
                                                     T
                                            ¼         þ 0          :
                                       1         k B T         R
                                    d
                                       T          h
            Aside we also need
                                            2    3
                                                                1           2
                     dT      d          d   6  1 7     d    1           1         2
                       ¼    (T) ¼       7          ¼             ¼ ( 1)      ¼ T :
                                            6
                      1       1          1  4  1  5     1   T           T
                   d       d          d              d
                      T       T          T    T         T
                                             SN1 solvolysis kinetics
                          0
                         0.0031   0.0032   0.0033  0.0034   0.0035  0.0036  0.0037
                         –2
                         –4
                       ln (K rate )  –6


                         –8

                        –10
                                            y =–10864x +28.336
                                             2
                                            R =0.9998
                        –12
                        –14
                                                  1/T (°K)
            FIGURE 8.3 Plot of ln(K) versus (1=T) for the solvolysis reaction.
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