Page 28 - Failure Analysis Case Studies II
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                                   Fig. 8. Polished cross-section through the shaft, showing the case-hardened layer


                                      Table 2.  Hardness measurements on shaft cross-section as a function
                                                 of radial distance from the centre
                                      r (mm)         HV       ~TS (MW    k, (MPa)
                                      0              350        1120       700
                                      10             360        1152       720
                                      17.5           375        1200       750
                                      22.5           400        1280       800
                                      Case           880        2816      1760



                      measured hardness  at the centre is HV  350, which agrees well  with  the predictions  of  the CCT
                      diagram. It is normal  practice to temper case-hardened  components in the range  15G18O"C in
                      order to improve the toughness [3]. Only if tempering had been carried out above 300 "C would there
                      have been any significant decrease in the hardness of the core. Accordingly, the close correspondence
                      between the measured hardness and the predicted as-quenched hardness does not necessarily indicate
                      that the shaft had been inadequately tempered.
                        Table 2 shows that the hardness of the case (HV 880) is significantly higher than that specified
                      (HV 68G780). However, there was no indication that this contributed to the failure. As shown in
                      Figs 3 and 4, the splines were able to withstand  a considerable shear strain even though they were
                      case-hardened. The maximum engineering shear strain suffered by the splines was
                                               y = 1.3 mm/l5 mm = 0.087 = 8.7%,                (1)
                      equivalent to a plastic strain in uniaxial tension [4] of




                                         3.  ESTIMATING  THE FAILURE  TORQUE

                        Referring to Fig. 10, it can be seen that the torque required to cause the shear fracture of a narrow
                      concentric band of the cross-section is
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