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                    76  Chapter 3  Water Sources: Groundwater


                                         Table 3.3  Variation of Drawdown with Time for Example 3.2
                                                    Time, days          u            W(u)        Drawdown, s, ft (m)
                                         (a)         1>1440         2.86   10  6     12.19          30.6 (9.33)
                                          (b)         1>24          4.8   10  8      16.27          40.8 (12.44)
                                          (c)         1>3           6.0   10  9      18.35          46.0 (14.02)
                                          (d)          1            2.0   10  9      19.45          48.8 (14.87)
                                          (e)          30           6.6   10  11     22.86          57.3 (17.46)
                                          (f)         180           1.1   10  11     24.66          61.8 (18.84)

                                                                           2
                                                        From Eq. 3.16:  u = 1.87 r S>Tt
                                                                                                 4
                                                                             2
                                                                                       -5
                                                                      = 1.87 * 1 * 3.4 * 10 >(3.2 * 10 )t
                                                                              -9
                                                                      = (2.0 * 10 )>t
                                             For various values of t, compute u, then from Table 3.2 obtain the well function, W(u), for the cal-
                                          culation of drawdown. The values of drawdown for various values of time are given in Table 3.3.
                                          Solution 2 (SI Units):
                                                        From Eq. 3.12: s = [Q>(4pT)][W(u)]
                                                                      = [3,815>(4 * 3.14 * 398.72)][W(u)]
                                                                      = 0.72 m[W(u)]
                                                                       2
                                                        From Eq. 3.13:  u = r S>(4Tt)
                                                                            2
                                                                                       -5
                                                                      = (0.3048) * 3.43 * 10 >(4 * 398.72t)
                                                                              -9
                                                                      = (2.0 * 10 )>t
                                             For various values of t, compute u, then from Table 3.2 obtain the well function, W(u), for the cal-
                                          culation of drawdown. The values of drawdown for various values of time are given in Table 3.3.





                    3.10.2 Semilogarithmic Approximation

                                         It was recognized that when u is small, the sum of the terms beyond ln u in the series expansion
                                         of W(u) (Eq. 3.14) is relatively insignificant. The Theis equation (Eq. 3.12) then reduces to:
                                                                                 2
                                                            s   [Q>(4 T)]{ln[(4Tt)>(r S)]   0.5772}
                                                                                  2
                                                            s   Q>(4 T) ln[(2.25Tt)>(r S)] (SI Units)        (3.17)
                                                      3
                                                               3
                                         where Q is in m /d, T in m /d/m, t in days, and r in m
                                         When Q is in gpm, T in gpd/ft, t in days, and r in ft, the equation becomes:
                                                                                   2
                                                            s   264(Q>T) log[(0.3Tt)>(r S)] (U.S. Customary Units) (3.18)
                                             A graphical solution was proposed for this equation. If the drawdown is measured in a
                                          particular observation well (fixed r) at several values of t, the equation becomes:
                                                                     s   264(Q>T) log(Ct)
                                          where
                                                                                 2
                                                                       C   0.3T>(r S)
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