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                    484  Chapter 13  Hydraulics of Sewer Systems


                     EXAMPLE 13.14  WATER SPREAD AND DEPTH OF FLOW IN THE GUTTER
                                                                 3
                                                        3
                                         For a flow of 1.0 ft /s (0.0283 m /s), a longitudinal street grade of 2.0%, a mean crosswise street
                                         grade of 5.6%, and an n coefficient of roughness of 0.015, find:
                                             1. The total width of spread, and
                                             2. The maximum depth of flow in the gutter.

                                         Solution 1 (U.S. Customary System):
                                             1. From Eq. 13.31:
                                                                 K c 1.67 0.5 2.67
                                                               Q =  S x S L T
                                                                  n
                                                                                      0.5
                                                              1 = (0.56>0.015)(0.056) 1.67 (0.02) (T 2.67 )
                                                             T 2.67  = 1>(37.3 * 0.0081 * 0.14) = 23.8
                                                             T   23.8 0.37    3.23 ft (0.98 m) water spread
                                             2. From Fig. 13.12:
                                                      d>T   S x
                                                       d   TS x   3.23   0.056   0.18 ft
                                                           2.2 in. (56 mm) maximum depth of flow in the gutter
                                          Solution 2 (SI System):

                                                       K c 1.67 0.5 2.67
                                             1.      Q =   S x   S L   T
                                                        n
                                                       0.376            0.5 2.67
                                                 0.0283 =    (0.056) 1.67  (0.02)   T
                                                       0.015
                                                       0.376 * 0.0081 * 0.1417  2.67
                                                 0.0283 =                   T
                                                               0.015
                                                   T 2.67  = 0.98
                                                      T = 0.985 m
                                             2. From Fig. 13.12:

                                                  d>T   S x
                                                    d   TS x   (0.985 m) (0.056)   0.055 m
                                                       55 mm





                     EXAMPLE 13.15  GRATE INLET
                                         If a 2-ft-wide (0.61-m) grate inlet is introduced in the gutter of Example 13.14, what will be the
                                         flow contained in the width of the grate?

                                         Solution 1 (U.S. Customary System):
                                                                                          3
                                             From Example 13.11, we get T   3.23 ft (0.98 m) and Q   1 ft /s (28.3 L/s). From Eq. 13.32:
                                                                E 0 = 1 - (1 - W g >T) 2.67
                                                                E 0 = 1 - (1 - 2>3.23) 2.67
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