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302                   Finite Element Modeling and Simulation with ANSYS Workbench



                                                 T(x, t)

                                                 x

            FIGURE 9.1
            The temperature field T(x, t) in a 1-D bar model.

            where,
              f  = heat flux per unit area
              x
              k = thermal conductivity
              T = T(x, t) = temperature field

              For 3-D case, we have:

                                                         ∂
                                            f x   ∂ Tx
                                                        
                                                         ∂
                                                   K
                                            f y  =−  ∂ Ty                           (9.2)
                                                   ∂ Tz 
                                                         ∂
                                             f z        
            where, f , f , f  = heat flux in the x, y, and z direction, respectively. In the case of isotropic
                     y
                       z
                   x
            materials, the conductivity matrix is:
                                                k   0     0
                                                
                                            K = 0    k   0                           (9.3)
                                                
                                                0   0     k
                                                         
              The equation of heat flow is given by
                                                              ∂T
                                        ∂f x
                                             ∂f y
                                                  ∂f z
                                     −    +    +      + q v  = ρ                      (9.4)
                                                            c
                                         ∂x  ∂y   ∂z         ∂t
            in which,
              q  = rate of internal heat generation per unit volume
               v
              c = specific heat
              ρ = mass density
              For steady-state case (∂T/∂t = 0) and isotropic materials, we can obtain:

                                              k∇ 2 T = − q v                           (9.5)
              This is a Poisson equation, which needs to be solved under given boundary conditions.
              Boundary conditions for steady-state heat conduction problems are (Figure 9.2):

                                             T =  T,on  S T                             (9.6)
                                                ∂ T
                                         Q ≡−  k   =  Q,on  S q                        (9.7)
                                                ∂ n

              Note that at any point on the boundary S =  S T ∪  S q , only one type of BCs can be specified.
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