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1656_C003.fm Page 157 Monday, May 23, 2005 5:42 PM
Elastic-Plastic Fracture Mechanics 157
where A* is the area enclosed by Γ*. By invoking the definition of strain energy density given by
Equation (3.20), we can evaluate the first term in square brackets in Equation (A3.14):
∂w = ∂w ∂ε ij = σ ∂ε ij
∂x ∂ε ij ∂ x ij ∂ x (A3.15)
Note that Equation (A3.15) applies only when w exhibits the properties of an elastic potential.
Applying the strain-displacement relationship (for small strains) to Equation (A3.15) gives
∂
∂w = σ ∂ ∂u i + ∂ u j
1
∂x 2 ij ∂x ∂x j ∂ x i
x
∂
∂ u (A3.16)
∂
= σ ij ∂x j x i
∂
since s = s . Invoking the equilibrium condition:
ij
ji
∂σ ij
∂x j = 0 (A3.17)
leads to
∂ u ∂ ∂ u ∂
i
σ ij x ∂ j x i = ∂ x ∂ j σ ij x ∂ (A3.18)
which is identical to the second term in square brackets in Equation (A3.14). Thus the integrand
in Equation (A3.14) vanishes and J = 0 for any closed contour.
Consider now two arbitrary contours Γ and Γ around a crack tip, as illustrated in Figure A3.3.
2
1
If Γ and Γ are connected by segments along the crack face (Γ and Γ ), a closed contour is formed.
3
1
2
4
The total J along the closed contour is equal to the sum of contributions from each segment:
J J = J + J + J + = 0 (A3.19)
1 2 3 4
FIGURE A3.3 Two arbitrary contours Γ 1 and Γ 2 around the tip of a crack. When these contours are connected
by Γ 3 and Γ 4 , a closed contour is formed, and the total J = 0.