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18                         2  Simulating Steady-State Natural Convective Problems
                               ∗
                              x
                       ∗
               T = θ(y ) cos q    + (1 − y )   (q = mπ, m = 1, 2, 3, ......).  (2.56)
                                          ∗
                ∗
                              L  ∗
              Substituting Eqs. (2.55) and (2.56) into Eqs. (2.53) and (2.54) yields the follow-
            ing equations:
                                       q           q
                                           2
                                  ∗           ∗           ∗
                             f (y ) −      f (y ) =  Raθ(y ),            (2.57)
                                      L  ∗         L ∗
                              q              q    2

                                                          ∗
                                    ∗
                                                  ∗
                                 f (y ) =−      θ(y ) + θ (y ).          (2.58)
                              L  ∗         L  ∗
              Combining Eqs. (2.57) and (2.58) leads to an equation containing f (y ) only:
                                                                      ∗
                             q            q            q
                                2             2           2
                  IV
                                     ∗
                                                               ∗

                     ∗
                 f  (y ) − 2     f (y ) −       Ra −        f (y ) = 0.  (2.59)
                            L  ∗          L  ∗        L  ∗
              It is immediately noted that Equation (2.59) is a linear, homogeneous ordinary
            differential equation so that it has a zero trivial solution. For the purpose of find-
            ing out a non-zero solution, it is noted that the non-zero solution satisfying both
            Equation (2.59) and the boundary conditions in Eqs. (2.46), (2.47) and (2.48) can
            be expressed as
                                    ∗
                           ∗
                         f (y ) = sin(ry )  (r = nπ, n = 1, 2, 3, ......).  (2.60)
              Using this equation, the condition under which the non-zero solution exists for
            Eq. (2.59) is derived and expressed as
                                  L  ∗  2  q     n       m     2
                                             2     2         2
                                                     ∗
                           Ra =     r +       =    L +       π
                                  q      L  ∗    m      L  ∗             (2.61)
                               (m = 1, 2, 3, ......, n = 1, 2, 3, ......).
                                                            ∗
              It can be observed from Eq. (2.61) that in the case of L being an integer, the
                                       2
                                                                        ∗
            minimum Rayleigh number is 4π , which occurs when n = 1 and m = L .How-
                                                                             2
                                                                         ∗ 2
                                                                  ∗
            ever, if L is not an integer, the minimum Rayleigh number is (L + 1 / L ) π ,
                   ∗
            which occurs when m = 1 and n = 1. Since the minimum Rayleigh number deter-
            mines the onset of natural convection in a fluid-saturated porous medium for the
            Horton-Rogers-Lapwood problem, it is often labelled as the critical Rayleigh num-
            ber, Ra critical .
              For this benchmark problem, the mode shapes for the stream function and
            related dimensionless variables corresponding to the critical Rayleigh number can
            be derived and expressed as follows:
                                          mπ

                                Ψ = C 1 sin   x  ∗  sin(nπy ),           (2.62)
                                                       ∗
                                           L  ∗
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