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Functions of Random Variables 153
In order to conform with conditions stated in this section, we augment Equa-
tion (5.78) by some simple transformation such as
Z X 2 :
5:79
The random variables Y and Z now play the role of Y 1 and Y 2 in Equation
(5.67) and we have
1
1
f YZ
y; z f X 1 X 2 g
y; z; g
y; zjJj;
5:80
1
2
where
y
1
g
y; z ;
1 z
1
g
y; z z;
2
1
1 y
z :
2
J z z
0 1
Using specific forms of f (x 1 ) and f (x 2 ) given in Example (5.11), Equation
X 1 X 2
(5.80) becomes
y 1 2y 2
z
f YZ
y; z f f
z ;
z X 2 z 2z
X 1
z
y
2
z
5:81
; for 0 y 2; and y z 2;
z 2
0; elsewhere:
Finally, pdf f Y (y) is found by performing integration of Equation (5.81) with
respect to z:
2
Z 1 Z y
2
z
f
y f YZ
y; z dz 2 dz;
Y
1 y z
2 y
ln y
1
ln 2; for 0 y 2;
0; elsewhere:
This result agrees with that given in Equation (5.47) in Example 5.11.
REFERENCE
Courant, R., 1937, Differential and Integral Calculus, Volume II, Wiley-Interscience,
New York.
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