Page 163 - Fundamentals of Radar Signal Processing
P. 163

illuminated circular and rectangular apertures.



                     The  corresponding  spatial  spectra  are  shown  in Fig.  2.28.  For  the
               rectangular aperture, it is a triangle function with a support of twice the aperture

               width. The reason is easy to see: the one-way voltage pattern is just the inverse
               Fourier transform of the aperture function, which for uniform illumination is a
               rectangular pulse of the width of the aperture. When that pattern is squared to get
               the  two-way  pattern,  the  Fourier  transform  of  the  squared  pattern  is  the  self-
               convolution  of  the  Fourier  transform  of  the  unsquared  pattern.  Thus,  the

               rectangular aperture function is convolved with itself to give a triangle of twice
               the aperture width. The spectrum for the circular aperture has the same width
               but is somewhat smoother.



























               FIGURE 2.28   Spatial spectra corresponding to the antenna patterns of Fig. 2.27.



                     The  spatial  spectra  of  these  idealized,  but  typical,  antenna  patterns  are
               lowpass  functions.  Thus,  the  upper  frequencies  in  the  spatial  spectrum  of  the
               observed data will be strongly attenuated and in fact effectively removed. Since

               resolution is proportional to bandwidth, Eq. (2.121) and Fig. 2.28 show that the
               antenna  pattern  reduces  resolution  because  it  has  a  strongly  lowpass  spatial
               spectrum.


               2.7.3   Variation with Range
               A development similar to that in Sec. 2.7.2 can be carried out to specialize Eq.
               (2.117) for the variation of received voltage in the range dimension along the
                                                      10
               boresight look direction (θ ,ϕ ).  First, interchange the order of integration in
                                                   0
                                                0
               Eq. (2.114) so that the outer integral is over range. Next, define the new quantity
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