Page 299 - Fundamentals of Reservoir Engineering
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OILWELL TESTING                                    235

                               1000
                                 9                                T  = 5000  T  = 2500
                                                                  F         F
                                 7
                                 6
                                 5
                                 4


                                 3



                                 2

                                100
                                  9
                                  7
                                  6
                                  5
                                  4


                                  3

                                                                   MATCH POINT
                           ∆  t   2                                  t = 60 mins
                          (mins)                                   ∆ p = 750 psi
                                 10                                ∆
                                  9
                                  7
                                  6
                                  5
                                  4


                                  3



                                  2
                                                                     ∆pF
                                                                      q  = 0.14
                                  10 -2  2      3      4  5  6  7  9  10 -1   2    3   4  5  6 7   9  1

                                                                   ∆pF
                                                                    q

                     Fig. 7.44  Match between McKinley type curves and superimposed observed buildup
                                (Exercise 7.9).
                                o − −− − match for small ∆ ∆∆ ∆t (T/F = 2500)
                                • • • • − −− − match for large ∆ ∆∆ ∆t (T/F = 5000)





                           ∆ pF    T    ∆ pF
                                                     ×
                                ×     =       =  0.14 2500 =   350
                            q      F      q
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