Page 155 - Fundamentals of The Finite Element Method for Heat and Fluid Flow
P. 155

STEADY STATE HEAT CONDUCTION IN MULTI-DIMENSIONS
                           Now, to calculate the loading vector, we need to determine the relevant coefficients,
                        that is,
                                                     2πhT a l ij                              147
                                                             = 120π                         (5.80)
                                                        6
                           Similarly,
                                                      2πql jk
                                                             = 1.8π                         (5.81)
                                                         6
                           Substituting the coefficients and other values into Equation 5.74, we obtain
                                                                   
                                                            3337.5 
                                                   {f}= 2π   3879.5                         (5.82)
                                                              − 18.5
                                                                   

                        5.7 Summary


                        In this chapter, an extension of the steady state heat conduction analysis to multi-dimensions
                        has been given. All commonly encountered approximations, namely, two-dimensional,
                        three-dimensional and axisymmetric, have been discussed. Most of the boundary conditions
                        have also been implemented and explained via examples. We trust the reader will appreciate
                        the difficulties associated with such multi-dimensional calculations and that the exercises
                        given in this chapter will prove useful for further understanding of multi-dimensional steady
                        state heat conduction.



                        5.8 Exercise

                        Exercise 5.8.1 A square plate of size 100 cm by 100 cm is subjected to an isothermal bound-
                                         ◦
                        ary condition of 500 C on the top and to a convection environment on all the remaining
                                                                             2
                                       ◦
                        three sides of 100 C with a heat transfer coefficient of 10 W/m K. The thermal conduc-
                                               2
                        tivity of the plate is 10 W/m K. Assume the thickness of the plate is 1 cm. Determine the
                        temperature distribution in the plate using (a) two triangles and (b) eight triangles. Cal-
                        culate the temperature and heat fluxes in the x and y directions at a location (x = 30 cm,
                        y = 30 cm).
                                                                                            3
                        Exercise 5.8.2 If in Exercise 5.8.1, there is a uniform heat generation of 2 W/cm , and
                        a line source of 5 W/cm at a location of (x = 30 cm and y = 30 cm) then, calculate the
                        new temperature distribution using (a) two triangles and (b) eight triangles. Calculate the
                        temperature at the location (x = 40 cm, y = 40 cm) and the heat fluxes in both the x and y
                        directions.

                        Exercise 5.8.3 Repeat Exercise 5.8.1 using (a) one rectangle (b) four rectangles.

                        Exercise 5.8.4 Repeat Exercise 5.8.2 using (a) one rectangle (b) four rectangles.
   150   151   152   153   154   155   156   157   158   159   160