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b

                 6.2-4. Equations of the Form y(x)+  G(···) dt = F (x)
                                                  a
                               b
               30.   y(x)+    f(t)y(t)y(xt) dt =0.
                            a
                      ◦
                     1 . Solutions:
                                              1  C         (I 1 – I 0 )x + I 1 – I 2  C
                                     y 1 (x)= –  x ,  y 2 (x)=        2    x ,
                                             I 0               I 0 I 2 – I
                                                                     1
                                                 b

                                          I m =   f(t)t 2C+m  dt,  m =0, 1, 2,
                                                a
                     where C is an arbitrary constant.
                                                                                k
                        There are more complicated solutions of the form y(x)= x C  n    B k x , where C is an
                                                                          k=0
                     arbitrary constant and the coefficients B k can be found from the corresponding system of
                     algebraic equations.

                     2 . A solution:
                      ◦
                                                           β
                                                   (I 1 – I 0 )x + I 1 – I 2  C
                                            y 3 (x)=                x ,
                                                        I 0 I 2 – I  2
                                                              1
                                                  b
                                          I m =   f(t)t 2C+mβ  dt,  m =0, 1, 2,
                                                a
                     where C and β are arbitrary constants.
                                                                               kβ
                        There are more complicated solutions of the form y(x)= x C  n    D k x , where C and β
                                                                         k=0
                     are arbitrary constants and the coefficients D k can be found from the corresponding system
                     of algebraic equations.

                     3 . A solution:
                      ◦
                                                       C
                                                      x (J 1 ln x – J 2 )
                                               y 4 (x)=            ,
                                                         J 0 J 2 – J 2
                                                               1
                                                b

                                                           m
                                         J m =   f(t)t 2C (ln t) dt,  m =0, 1, 2,
                                               a
                     where C is an arbitrary constant.
                                                                                   k
                        There are more complicated solutions of the form y(x)= x C  n    E k (ln x) , where C is
                                                                          k=0
                     an arbitrary constant and the coefficients E k can be found from the corresponding system of
                     algebraic equations.
                     4 . The equation also has the trivial solution y(x) ≡ 0.
                      ◦
                                            β
                     5 . The substitution y(x)= x w(x) leads to an equation of the same form,
                      ◦
                                             b
                                                                             2β
                                    w(x)+    g(t)w(t)w(xt) dt =0,  g(x)= f(x)x .
                                           a



                 © 1998 by CRC Press LLC









                © 1998 by CRC Press LLC
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