Page 102 - Handbook of Civil Engineering Calculations, Second Edition
P. 102

STATICS, STRESS AND STRAIN, AND FLEXURAL ANALYSIS  1.85

                              8. Compute the force on the rivets
                              Considering rivets 1 and 2, use the equation F   Mr
/J, where r
  distance from the in-
                              stantaneous center of rotation O to the center of the given rivet, in. For rivets 1 and 2, r
                              7.45 in. (189.230 mm). Then F   90,000(7.45)/118   5680 lb (25,264.6 N). The force on
                              rivet 1 has an action line normal to the radius OA.



                              DESIGN OF A WELDED LAP JOINT

                                                           3
                              The 5-in. (127.0-mm) leg of a 5   3   /8 in. (127.0   76.2   9.53 mm) angle is to be
                              welded to a gusset plate, as shown in Fig. 60. The member will be subjected to repeated
                              variation in stress. Design a suitable joint.
                              Calculation Procedure:

                              1. Determine the properties of the angle
                              In accordance with the AISC Specification, arrange the weld to have its centroidal axis
                              coincide with that of the member. Refer to the AISC Manual to obtain the properties of
                                                             2
                              the angle. Thus A   2.86 sq.in. (18.453 cm ); y 1   1.70 in. (43.2 mm); y 2   5.00   1.70
                                3.30 in. (83.820 mm).
                              2. Compute the design load and required weld length
                              The design load P lb (N)   As   2.86(22,000)   62,920 lb (279,868.2 N). The AISC
                              Specification restricts the weld size to  /16 in. (7.94 mm). Hence, the weld capacity
                                                           5
                              5(600) 3000 lb/lin in (525,380.4 N/m); L   weld length, in. (mm)   P/capacity, lb/lin in
                                62,920/3000   20.97 in. (532.638 mm).
                              3. Compute the joint dimensions
                              In Fig. 60, set c   5 in. (127.0 mm), and compute a and b by applying the following equa-
                              tions: a   Ly 2 /w   c/2; b   Ly 1 /w   c/2. Thus, a   (20.97   3.30)/5   /2   11.34 in.
                                                                                    5
                                                           5
                              (288.036 mm); b   (20.97   1.70)/5   /2   4.63 in. (117.602 mm). Make a   11.5 in.
                              (292.10 mm) and b   5 in. (127.0 mm).




















                                     FIGURE 60
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