Page 178 - Handbook of Civil Engineering Calculations, Second Edition

STRUCTURAL STEEL DESIGN 1.161

A s F y 11.8 sq.in. 36 ksi 425 kips (1890 kN)
V h 425 kips (1890 kN)
3. Find the number of shear studs required
The nominal strength of a single shear stud [from Eq. (15-1)] is

Q n 0.5A sc f c
E c A sc F u
3
For a /4-in.-diameter stud,

0.75 in. 2 2
A sc 0.44 sq.in. (2.84 cm )
2

E c w 1.5 f c
145 1.5 5.0 3904 ksi (26,899 kNm)
F u 60 ksi (413 kNm)

Q n 0.5 0.44 sq.in. 5.0 ksi 3904 ksi 0.44 sq.in. 60 ksi (413
kNm)
30.9 kips 26.4 kips (117.4 kN)
26.4 kips per stud (117.4 kN per stud)
The number of shear connectors between the points of zero and maximum moments is
V h 425 kips
n kips/stud
Q n 26.4
16.1 or 17 studs
For the beam shown in Fig. 48, the required number of shear studs is 2n 2 17 34.
Assuming a single line of shear studs (over the beam web), stud spacing 30.0 ft/34
0.88 ft 10.6 in. (26.9 cm). This is greater than the six-stud diameter [or 6 /4 in.
3
4.5 in. (11.4 cm)] minimum spacing, and less than the eight slab thickness [or 8 5 in.
40 in. (101.6 cm)] maximum spacing, which is satisfactory.
Related Calculations. This procedure is the work of Abraham J. Rokach, MSCE, As-
sociate Director of Education, American Institute of Steel Construction. SI values were
prepared by the handbook editor.

FIGURE 48