Page 241 - Handbook of Civil Engineering Calculations, Second Edition
P. 241

2.26    REINFORCED AND PRESTRESSED CONCRETE ENGINEERING AND DESIGN

                            3. Select the stirrup size
                            Use the method given earlier in the ultimate-strength calculation procedure to select the
                            stirrup size, establish the maximum allowable spacing, and devise a satisfactory spacing.


                            CAPACITY OF A T BEAM

                            Determine the flexural capacity of the T beam in Fig. 16a, using f c 
  3000 lb/sq.in.
                            (20,685 kPa).


                            Calculation Procedure:

                            1. Record the pertinent beam values
                            The neutral axis of a T beam often falls within the web. However, to simplify the analy-
                            sis, the resisting moment developed by the concrete lying between the neutral axis and the
                            flange is usually disregarded. Let A f denote the flange area. The pertinent beam values are
                            f c,allow   1350 lb/sq.in. (9308.3 kPa); n   9; k b   0.378; nA s   9(4.00)   36.0 sq.in.
                                   2
                            (232.3 cm ).
                            2. Tentatively assume that the neutral axis lies in the web
                            Locate this axis by taking static moments with respect to the top line. Thus A f   5(16)
                                         2
                            80 sq.in. (516.2 cm ); kd   [80(2.5)   36.0(21.5)]/(80   36.0)   8.40 in. (213.36 mm).
                            3. Identify the controlling stress
                            Thus k   8.40/21.5   0.391 > k b ; therefore, concrete stress governs.
                            4. Calculate the allowable bending moment
                                                                                   1
                            Using Fig. 16c, we see f c1   1350(3.40)/8.40   546 lb/sq.in. (3764.7 kPa); C   /2(80)(1350
                              546)   75,800 lb (337,158.4 N). The action line of this resultant force lies at the centroidal
                            axis of the stress trapezoid. Thus, z   ( /3)(1350   2   546)/(1350   546)   2.15 in. (54.61
                                                       5
                            mm); or z   ( /3) (8.40   2   3.40)/(8.40   3.40)   2.15 in. (54.61 mm); M   Cjd
                                      5
                            75,800(19.35)   1,467,000 in.·lb (165,741 N·m).





















                            FIGURE 16
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