Page 238 - Handbook of Civil Engineering Calculations, Second Edition
P. 238

REINFORCED CONCRETE                  2.23

                              DESIGN OF REINFORCEMENT IN A
                              RECTANGULAR BEAM OF GIVEN SIZE

                              A rectangular beam of 4000-lb/sq.in. (27,580-kPa) concrete has a width of 14 in. (355.6
                              mm) and an effective depth of 23.5 in. (596.9 mm). Determine the area of reinforcement
                              if the beam is to resist a bending moment of (a) 220 ft·kips (298.3 kN·m); (b) 200 ft·kips
                              (271.2 kN·m).


                              Calculation Procedure:

                              1. Calculate the moment capacity of this member
                              at balanced design
                              Record the following values: f c,allow   1800 lb/sq.in. (12,411 kPa); n   8. From Table 1,
                                                                                    2
                                                                       2
                              j b   0.860; K b   324 lb/sq.in. (2234.0 kPa); M b   K b bd   324(14)(23.5)   2,505,000
                              in.·lb (283,014.9 N·m).
                              2. Determine which material will be stressed to capacity under
                              the stipulated moment
                              For part a, M   220,000(12)   2,640,000 in.·lb (3,579,840 N·m) > M b . This result signi-
                              fies that the beam size is deficient with respect to balanced design, and the concrete will
                              therefore be stressed to capacity.

                              3. Apply the basic equations in proper sequence to obtain A s
                                                                              2
                                                     2
                              By Eq. 24, k(3   k)   6M/( f c bd )   6(2,640,000)/[1800(14)(23.5) ]   1.138; k   0.446.
                                                                2
                              By Eq. 29,  p   k /[2n(1    k)]    0.446 /[16(0.554)]    0.0224;  A s   pbd
                                              2
                                                             2
                              0.0224(14)(23.5)   7.37 sq.in. (47.551 cm ).
                              4. Verify the result by evaluating the flexural capacity
                              of the member
                              For part b, compute A s by the exact method and then describe the approximate method
                              used in practice.
                              5. Determine which material will be stressed to capacity under
                              the stipulated moment
                              Here M   200,000(12)   2,400,000 in.·lb (3,254,400 N·m) < M b . This result signifies
                              that the beam size is excessive with respect to balanced design, and the steel will therefore
                              be stressed to capacity.

                              6. Apply the basic equations in proper sequence to obtain A s
                                           2
                              By using Eq. 27, k (3   k)/(1   k)   6nM/(f s bd )   6(8)(2,400,000)/[20,000(14)(23.5) ]
                                                                2
                                                                                           2
                              0.7448; k   0.411. By Eq. 22, j   1   0.411/3   0.863. By Eq. 25, A s   M/( f s jd)
                                                                        2
                              2,400,000/[20,000(0.863)(23.5)]   5.92 sq.in. (38.196 cm ).
                              7. Verify the result by evaluating the flexural capacity
                              of this member
                              The value of j obtained in step 6 differs negligibly from the value j b   0.860. Conse-
                              quently, in those instances where the beam size is only moderately excessive with respect
                              to balanced design, the practice is to consider that j   j b and to solve Eq. 25 directly on
                              this basis. This practice is conservative, and it obviates the need for solving a cubic equa-
                              tion, thus saving time.
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