Page 418 - Handbook of Energy Engineering Calculations
P. 418

bulb temperature met in summer is 90°F (32.2°C). Use this as the air inlet
               temperature.
                  Before  the  required  surface  area  can  be  determined,  the  air  outlet
               temperature from the radiator must be known. This outlet temperature cannot
               be computed directly. Hence, it must be assumed and a trial calculation made.

               If  the  area  obtained  is  too  large,  a  higher  outlet  air  temperature  must  be
               assumed  and  the  calculation  redone.  Assume  an  outlet  air  temperature  of
               150°F (65.6°C).


               4. Compute the LMTD for the radiator

               The  largest  temperature  difference  for  this  exchanger  is  160  –  90  =  70°F
               (38.9°C),  and  the  smallest  temperature  difference  is  150  –  140  =  10°F
               (5.6°C). In the smallest temperature difference expression, 140°F (77.8°C) =
               water discharge temperature from the engine – cooling-water temperature rise

               during  passage  through  the  engine,  or  160  –  20  =  140°F  (77.8°C).  Then
               LMTD = (70 – 10)/[ln (70/10)] = 30°F (16.7°C). (Figure 4 could also be used
               to compute the LMTD.)


               5. Compute the required exchanger surface area
                                                                                                     2
               Use the relation A = Q/U × LMTD, where A = surface area required, ft ; Q =
               rate of heat transfer, Btu/h; U = overall coefficient of heat transfer, Btu/(h ·
                 2
               ft  · °F). To solve this equation, U must be known.
                  Table  1  in  the  first  calculation  procedure  in  this  section  shows  that  U
                                                                          2
                                                    2
               ranges from 2 to 10 Btu/(h · ft  · °F) [56.8 W/(m  · °C)] in the usual internal-
               combustion-engine finned-tube radiator. Using a value of 5 for U, we get A =
                                                                  2
                                                    2
               2,200,000[(5)(30)] = 14,650 ft  (1361.0 m ).

               6. Determine the length of finned tubing required
               The total area of a finned tube is the sum of the tube and fin area per unit
               length. The tube area is a function of the tube diameter, whereas the finned

               area is a function of the number of fins per inch of tube length and the tube
               diameter.
                  Assume that 1-in (2.5-cm) tubes having 4 fins per inch (6.35 mm per fin)
               are used in this radiator. A tube manufacturer’s engineering data show that a

                                                                                                        2
                                                                  2
               finned tube of these dimensions has 5.8 ft  of area per linear foot (1.8 m /lin
               m) of tube.
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