Page 416 - Handbook of Energy Engineering Calculations
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3
                                  3
               ft /min (0.28 m /min).
                                                                                          3
                  Air entering with the cooling water varies from about 2 ft /min per 1000
                                                                                                      3
                                              3
               gal/min of 100°F (0.06 m /min per 3785 L/min of 37.8°C) water to 4 ft /min
                                                          3
               per 1000 gal/min at 35°F (0.11 m /min per 3785 L/min at 1.7°C). Using a
                              3
                                               3
               value of 3 ft /min (0.08 m /min) for this condenser, we see the quantity of air
                                                3
               that must be handled is (ft /min per 1000 gal/min)(cooling-water flow rate,
                                       3
                                                                                       3
               gal/min)(1000, or ft /min of air = (3)(13,000/1000) = 39 ft /min at 60°F (1.1
                                                                                                      3
                                                              3
                  3
               m /min at 15.6°C). At 80°F (26.7°C) ft /min = (3) (30,000/1000) = 90 ft /min
                       3
               (2.6 m /min).
                                                                                                      3
                  Hence, the total air quantity that must be handled is 39 + 10 = 49 ft /min
                        3
                                                                                                      3
               (1.4 m /min) with 60°F (15.6°C) cooling water, and 90 + 10 = 100 ft /min
                        3
               (2.8 m /min) with 80°F (26.7°C) cooling water. The air is usually removed
               from the barometric condenser by a two-stage air ejector.

               Related Calculations. For help in specifying conditions for parallel-flow and
               counterflow  barometric  condensers,  refer  to  Standards  of  Heat  Exchange
               Institute—Barometric and Low-Level Jet Condensers. Whereas Fig. 6 can be

               used for a first approximation of the cooling water required for parallel-flow
               barometric  condensers,  the  results  obtained  will  not  be  as  accurate  as  for
               counterflow condensers.


               FINNED-TUBE HEAT-EXCHANGER SELECTION




               Choose  a  finned-tube  heat  exchanger  for  a  1000-hp  (746-kW)  four-cycle
               turbocharged  diesel  engine  having  oil-cooled  pistons  and  a  cooled  exhaust

               manifold. The heal exchanger will be used only for jacket-water cooling.


               Calculation Procedure:


               1. Determine the heat-exchanger cooling load
               The Diesel Engine Manufacturers Association (DEMA) tabulation, Table 3,
               lists  the  heat  rejection  to  the  cooling  system  by  various  types  of  diesel
               engines. Table 3 shows that the heat rejection from the jacket water of a four-

               cycle turbocharged engine having oil-cooled pistons and a cooled manifold is
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