Page 91 - Handbook of Energy Engineering Calculations
P. 91

condenser. Likewise, the net areas for W , W , and W , Fig. 16a, are all too
                                                                                 4
                                                                  2
                                                                       3
               large, because less than 1 lb (0.5 kg) of steam flows through the respective
               turbine sections. The area for W , however, is true.
                                                      1
                  A true proportionate-area diagram can be plotted by applying the factors
               for actual flow as in Fig. 16b. Here W , outlined by the heavy lines, equals
                                                               2
               the  similarly  labeled  area  in  Fig.  16a,  multiplied  by  1  −  m .  The  states
                                                                                             1
               marked 11′ and 12′, Fig. 16b, are not true state points because of the ratioing

               factor applied to the area for W . The true state points 11 and 12 of the liquid
                                                     2
               before and after heater pump 3 stay as shown in Fig. 16a.

                  Apply 1 − m  − m  to W  of Fig. 16a. to obtain the proportionate area of
                                  1
                                         2
                                                 3
               Fig. 16b; to obtain W , multiply by 1 − m  − m  − m . Multiplying by this
                                                                    1
                                          4
                                                                                  3
                                                                           2
               factor  also  gives  Q .  Then  all  the  areas  in  Fig.  16b  will  be  in  proper
                                         r
               proportion for 1 lb (0.5 kg) of steam entering the turbine throttle but less in
               other parts of the cycle.
                  In Fig. 16b, the work can be measured by the difference of the area Q  and
                                                                                                       a
               the area Q . There is no simple net area left, because the areas coincide on
                            r
               only two sides. But area enclosed by the heavy lines is the total net work W

               for the cycle, equal to the sum of the work produced in the various sections of
               the turbine, Fig. 16b. Then Q  is the alternate area Q  + W  + W  + W  + W ,
                                                   a
                                                                                                    3
                                                                                                           4
                                                                                             2
                                                                               r
                                                                                      1
               as shaded in Fig. 16c.
                  The sawtooth approach of the liquid-heating line shows that as the number
               of heaters in the cycle increases, the heating line approaches a line of constant
               entropy. The best number of heaters for a given cycle depends on the steam
               state  of  the  turbine  inlet.  Many  medium-pressure  and  medium-temperature

               cycles use five to six heaters. High-pressure and high-temperature cycles use
               as many as nine heaters.


               4. Draw the energy-flow chart
               Choose a suitable scale for the heat content of 1 lb (0.5 kg) of steam leaving
               the steam generator. A typical scale is 0.375 in per 1000 Btu/lb (0.41 cm per

               1000 kJ/kg). Plot the heat content of 1 lb (0.5 kg) of steam vertically on line
               2-2, Fig. 17. Using the same scale, plot the heat content in energy streams m ,
                                                                                                           1
               m , m , W , W, W , W , and so forth. In some cases, as W , W ,  and  so
                                                                                                 p2
                       3
                            e
                                      p
                                           pF
                                                                                          p1
                  2
               forth, the energy stream may be so small that it is impossible to plot it to
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