Page 194 - How To Solve Word Problems In Calculus
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                                It is clear from a diagram that f (x) ≥ g(x) for x ε [−1, 2].

                                                  10 10
                                                           (x,y )         Only one “imaginary”
                                                              2
                                                   8 8                    rectangle is shown. Imag-
                                                                          ine an infinite number.
                                                   6 6
                                                        (x,y )
                                                            1
                                                   4 4

                                                   2 2


                                − −3 3  − 2  − −1 1        1 1    2 2    3 3
                                      −2

                                We are now ready to compute the area of the region bounded
                                by the curves.
                                                    b

                                              A =    (y 2 − y 1 ) dx
                                                   a
                                                    2

                                                =    [ f (x) − g(x)] dx
                                                   −1
                                                    2

                                                           2
                                                =    [9 − x − (7 − x)] dx
                                                   −1
                                                    2

                                                           2
                                                =    [2 − x + x] dx
                                                   −1
                                                         x    x
                                                          3    2 2

                                                = 2x −      +
                                                         3    2   −1

                                                        8               1    1
                                                = 4 −     + 2 − −2 +      +
                                                        3               3    2

                                                  10       7
                                                =    − −
                                                   3       6
                                                  9
                                                =
                                                  2
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