Page 314 - Solutions Manual to accompany Electric Machinery Fundamentals
P. 314

Chapter S1:           Introduction to Power Electronics


          S1-1.  Calculate  the  ripple  factor  of a three-phase half-wave rectifier circuit, both analytically and using
                 MATLAB.

                 SOLUTION  A three-phase half-wave rectifier and its output voltage are shown below

















                                                         /6  5/6





                                                            2/3




                                                                 V
                                                             vt      M  sin t
                                                              A
                                                                                
                                                                 V
                                                             vt      M  sin  t  2 /   3
                                                              B
                                                                 V
                                                                                
                                                             vt      M  sin  t  2 /   3
                                                              C
                 SOLUTION  If we find the average and rms values over the interval from /6 to 5/6 (one period), these
                 values will be the same as the average and rms values of the entire waveform, and they can be used to
                 calculate the ripple factor.  The average voltage is
                                            
                            1            3  5/ 6
                      V DC      v () t dt     V M  sin    t d  t 
                                        2
                            T
                                             /6
                                         5
                              3V         6   3V     3    3   3 3
                      V DC    2  M  cos t         2  M       2    2       2   V   0.8270 V
                            
                                                                                  M
                                                                      M
                            
                                         6
                 The rms voltage is
                                                
                              1              3  5/ 6
                                                                  
                                                         2
                      V          v () t  2 dt     V  2 sin    t d  t
                        rms                         M
                              T              2  /6
                                                    
                              3V M   2  1  1      5/ 6
                      V               t   sin2   t
                        rms    2     2  4          /6


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