Page 80 - Solutions Manual to accompany Electric Machinery Fundamentals
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(d)  The induced torque would be:
                          ind    2rilΒ  sin                                                   (3-17)
                             t
                          ind   2t   0.1 m 2.26 sin  t     A 0.3 m 1.0 T  sin  t  
                                         2
                          ind  t    0.136 sin  377  N m, counterclockwise
                                                 
                                              t
                 (e)  The instantaneous power generated by the loop is:
                           e i
                         Pt     ind    22.6 sin377  V 2.26 sin 377  At    t   51.1 sin 377   Wt  2
                 The average power generated by the loop is

                         P   1  T   51.1 sin    t dt   25.55 W
                                         2
                          ave
                              T
                 (f)   The mechanical power being consumed by the loop is:
                         P    ind  0.136 sin  377  N mt    377 rad/s  51.3 sin   2  t  W
                           
                                            2
                 Note that the amount of mechanical power consumed by the loop is equal to the amount of electrical
                 power created by the loop (within roundoff error).  This machine is acting as a generator, converting
                 mechanical power into electrical power.
          3-2.   Develop a table showing the speed of magnetic field rotation in ac machines of 2, 4, 6, 8, 10, 12, and 14
                 poles operating at frequencies of 50, 60, and 400 Hz.
                 SOLUTION  The equation relating the speed of magnetic field rotation to the number of poles and electrical
                 frequency is
                              120 f
                         n       se
                          sm
                                P
                 The resulting table is
                               Number of Poles     f  = 50 Hz    f  = 60 Hz    f  = 400 Hz
                                                   e
                                                                 e
                                                                               e
                                      2           3000 r/min    3600 r/min    24000 r/min
                                      4           1500 r/min    1800 r/min    12000 r/min
                                      6           1000 r/min    1200 r/min     8000 r/min
                                      8            750 r/min     900 r/min     6000 r/min
                                      10           600 r/min     720 r/min     4800 r/min
                                      12           500 r/min     600 r/min     4000 r/min
                                      14          428.6 r/min   514.3 r/min    3429 r/min

          3-3.   The first ac power system in the USA ran at a frequency of 133 Hz.  If the ac power for this system were
                 produced by a 4-pole generator, how fast would the shaft of the generator have to rotate?

                 SOLUTION  The equation for the speed of the shaft is
                              120 f   120       133 Hz
                         n       se               3990 r/min
                          sm
                                P          4
          3-4.   A three-phase Y-connected four-pole winding is installed in 24 slots on a stator.  There are 40 turns of
                 wire in each slot of the windings.  All coils in each phase are connected in series.  The flux per pole in the
                 machine is 0.060 Wb, and the speed of rotation of the magnetic field is 1800 r/min.
                     (a)  What is the frequency of the voltage produced in this winding?
                     (b)  What are the resulting phase and terminal voltages of this stator?

                 SOLUTION
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