Page 209 - Intro to Tensor Calculus
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               The equation (2.2.61) implies that ω i and ω ij are dual tensors and

                                                             1
                                                        ω i =  e ijk ω jk .
                                                             2
               Also the velocity of a point which is rotating about the origin relative to the S frame of reference is v i (S)=
               e ijk ω j x k which can also be written in the form v m (S)= −ω mk x k . Since the barred axes rotate with the rigid
               body, then a particle in the barred reference frame will have v m (S) = 0, since the coordinates of a point
               in the rigid body will be constants with respect to this reference frame. Consequently, we write equation
                                                ˙
               (2.2.59) in the form 0 = v m (S)+ ` mi ` ji x j which implies that
                                               ˙                                        ˙
                                  v m (S)= −` mi` ji x j = −ω mk x k  or ω mj = ω mj (S, S)= ` mi ` ji .

               This equation is interpreted as describing the angular velocity tensor of S relative to S. Since ω ij is a tensor,
               it can be represented in the barred system by

                                                  ω mn (S, S)= ` im ` jn ω ij (S, S)
                                                                     ˙
                                                           = ` im ` jn ` is ` js
                                                                                                      (2.2.62)
                                                                    ˙
                                                           = δ ms ` jn ` js
                                                                ˙
                                                           = ` jn ` jm
               By differentiating the equations (2.2.51) it is an easy exercise to show that ω ij is skew-symmetric. The
               second order angular velocity tensor can be used to write the equations (2.2.59) and (2.2.60) in the forms


                                                 v m (S)= v m (S)+ ω mj (S, S)x j
                                                                                                      (2.2.63)
                                                 v m (S)= v m (S)+ ω jm (S, S)x j
               The above relations are now employed to derive the celebrated Euler’s equations of motion of a rigid body.

                   Euler’s Equations of Motion

                   We desire to find the equations of motion of a rigid body which is subjected to external forces. These
               equations are the formulas (2.2.49), and we now proceed to write these equations in a slightly different form.
               Similar to the introduction of the angular velocity tensor, given in equation (2.2.61), we now introduce the
               following tensors
                   1. The fourth order moment of inertia tensor I mnst which is related to the second order moment of
               inertia tensor I ij by the equations

                                                 1                     1
                                          I mnst =  e jmn e ist I ij  or I ij =  I pqrs e ipq e jrs   (2.2.64)
                                                 2                     2
                   2. The second order angular momentum tensor H jk which is related to the angular momentum vector
               H i by the equation
                                                    1
                                               H i =  e ijk H jk  or H jk = e ijk H i                 (2.2.65)
                                                    2
                   3. The second order moment tensor M jk which is related to the moment M i by the relation

                                                    1
                                              M i =  e ijk M jk  or M jk = e ijk M i .                (2.2.66)
                                                    2
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