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P. 160

4.5 Numerical Stability by Energy Arguments
        Finally, we use the inequality
                                  13
                                        (a + b )
                                  ab ≤
                                          2
                                       2
        to obtain
               n
                                     n


                       m
                             m
                                             ) + ((v
                 v
                          + v
                     (v
                                                         2
                  m+1
                                                                 2
                                ) ≤
                  j
                                                 2
                       j−1
                             j+1
                                                              j+1
                                                     j−1
                                    j=1
              j=1
                                     n

                                             ) +(v ) ).
                                       ((v
                                  ≤
                                         m+1 2
                                                   j
                                    j=1 1 ((v j j m+1 2 2  1  m 2 m  ) +(v m  ) ))  147
        Collecting these three inequalities, it follows from (4.47) that
                                                       n
                                      m
              E  m+1  − E m  ≤ r(E  m+1  − E ) − r(1 − 2r)∆x    (v m  − v )
                                                                 m 2
                                                                 j
                                                          j+1
                                                      j=1
                                      m
                         ≤ r(E  m+1  − E ),
        where we have used the stability assumption (4.44). Hence,
                                             m
                              (1 − r)(E m+1  − E ) ≤ 0,
        and by (4.44) this implies the desired inequality (4.46).
          We summarize the result of the discussion above:
                           m
        Theorem 4.1 Let {v } be a solution of the finite difference scheme (4.42)–
                           j
                                               m
        (4.43) and let the corresponding energy {E } be given by (4.45). If the
                                           m
        stability condition (4.25) holds, then {E } is nonincreasing with respect to
        m.
          Hence, we have seen that the stability condition (4.25), or (4.44), implies
        that the explicit difference scheme admits an estimate which is similar to
        the estimate (3.60) for the continuous problem. As for the continuous prob-
        lem, this can be used to estimate the difference between two solutions, with
        different initial data. This follows since the difference of two solutions of
        the finite difference scheme is a new finite difference solution. We therefore
        obtain
        Corollary 4.1 Assume that the stability condition (4.25) holds and let
                    m
          m
        {v } and {w } be two solutions of the finite difference scheme (4.42)–
          j         j
        (4.43). Then, for all m ≥ 0,
                           n
                                               0
                               m
                       ∆x    (v  − w ) ≤ ∆x     (v − w ) .
                                                  0
                                     m 2
                                                       0 2
                               j    j             j    j
                          j=1                 j=1
          13 See Exercise 4.24.
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