Page 426 - Introduction to AI Robotics
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11.6 Comparison of Methods
                                                        (1 :0)(0  :46)                                409
                                      m(dontknow  )  =            =  :46                              0
                                                        1:0  0:0
                                        Therefore, the updated belief at g  r[3][10]  i d is:
                                         ccupied
                             (11.15)  m(O        )   :54 ;  (E  m) =m :0;  (dontknow  m t =) y  :46  0 =            0                      0
                                                                           p
                                        The HIMM updating is governed by Eqn. 11.11, below. Since g  r[3][10]  i d is
                                      in the HIMM occupied region, the increment term I is I +  = .                          3


                                      g  r[3][10]  i d  =  g  r[3][10]+ i d  I +
                                                 =  0                  +                           3                 =                           3


                                      Step 4: Repeat Steps 2 and 3 for each new reading.
                                      At t 2 , the robot has translated forward. The sonar reading is 6.0. The grid
                                      element is now 6.0 units away with an   =    . g  r[3][10]  i d still falls in Region  0
                                      I for all three updating methods. The application of Eqn. 11.1 produces a
                                                                                                  =
                                      probability of P (sjOccupied  )  :69 ;  (sjE  P  ) =m  :31 , a  p belief  tfunction of  0       0
                                                                                                   y
                                         ccupied
                                                                  )
                                      m(O        ) = 0:69 ;  (E  m m= 0:0;  ( pdontknow  t m  y) = 0:31 ,and a HIMM
                                      increment of +3.
                                        Updating the grid produces an increase in the occupancy score, as would
                                      be expected, given two direct sonar observations of an object. The Bayesian
                                      updating is:

                                                                           )
                                                                 jO)P (Ojs t 1
                                                            P (s t 2
                                             )  =
                                      P (Ojs t 2
                                                                  )       jE)P (E j  )
                                                   P (s t 2  jO)P (Ojs t 1  P (s t 2  +s t 1
                                                          (0 :69)(0  :54)
                                                =
                                                            (0
                                                   (0 :69)(0  :54)+  :31)(0  :46)
                                                =  0:72
                                             )  =  1         )    :28          =                                   0
                                      P (Ejs t 2       P (Ojs t 2
                                        The Dempster-Shafer updating generates a higher occupancy score, which
                                      can also be seen from Fig. 11.16b. The final score is:
                                                                (0
                                                                             (0
                                                        (0 :54)(0  :69)+  :46)(0  :69)+  :54)(0  :31)
                                         ccupied
                                      m(O        )  =
                                                                      1:0  0:0
                                                    =  0:86
                                                        (0 :46)(0  :31)
                                      m(dontknow  )  =             =  :14                              0
                                                         1:0  0:0
                                           mpty
                                        m(E      )  =  0:0
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