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7.9 Geostatistics (by R. Gebbers)                               183

           processes. Before we discuss further aspects of variogram modeling let us

           just fit some models to our data. We are beginning with a spherical model
           without nugget, than adding an exponential and a linear model, both with
           nugget variance:

             plot(DE,GE,'.' )
             var_z = var(z)
             b = [0 max(DE)];
             c = [var_z var_z];
             hold on
             plot(b,c, '--r')
             yl = 1.1*max(GE);
             ylim([0 yl])
             xlabel('lag distance')
             ylabel('variogram')
             lags=0:max(DE);
             % Spherical model with nugget
             nugget = 0;
             sill = 0.803;
             range = 45.9;
             Gsph = nugget + (sill*(1.5*lags/range-0.5*(lags/...
                range).^3).*(lags<=range)+ sill*(lags>range));
             plot(lags,Gsph,'-g')
             ylim([0 1.1*var_z])
             % Exponential model with nugget
             nugget = 0.0239;
             sill = 0.78;
             range = 45;
             Gexp = nugget + sill*(1 - exp(-3*lags/range));
             plot(lags,Gexp,'-b')
             % Linear model with nugget
             nugget = 0.153;
             slope = 0.0203;
             Glin = nugget + slope*lags;
             plot(lags,Glin,'-m')
             hold off

           Variogram modeling is very much a point of discussion. Some advocate  ob-

           jective variogram modeling by automated curve fitting, using a weighted least
           squares, maximum likelihood or maximum entropy method. Contrary to this
           it is often argued that the geological knowledge should be included in the
           modeling process and thus, fitting by eye is recommended. In many cases the

           problem in variogram modeling is much less the question of the appropriate
           procedure but a question of the quality of the experimental variogram. If the
           experimental variogram is good, both procedures will yield similar results.
             Another question important for variogram modeling is the intended use
           of the model. In our case, the linear model seems not to be appropriate
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