Page 69 - Marks Calculation for Machine Design
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P1: Sanjay
                          January 4, 2005
                                      16:18
        Brown.cls
                 Brown˙C02
                                                                                   51
                                                 BEAMS
                      Note that the bending moment (M) is zero at both ends, and increases linearly to a
                    maximum positive value (Ca/L) where the couple acts. At the point where the couple
                    acts, that is at a distance (a), there is a discontinuity in the bending moment of magnitude
                    (C) downward. So from where the couple acts, the bending moment starts at a maxi-
                    mum negative value (−Cb/L) and increases linearly back to zero. Note that the slopes
                    of these two increasing values of bending moment are equal, and therefore the lines are
                    parallel.
                      If the distance (a) is less than the distance (b), then the maximum bending moment
                    (M max ) is given by Eq. (2.14a). If the distance (a) is greater than the distance (b), then the
                    maximum bending moment (M max ) is given by Eq. (2.14b).
                                                  Cb
                                           M max =      a < b                  (2.14a)
                                                  L
                                                  Ca
                                           M max =      a > b                  (2.14b)
                                                  L
                      If the distance (a) is equal to the distance (b), which means are the couple (C) acts at
                    the midpoint of the beam, then (a) and (b) each is equal to half the length of the beam (L).
                    Therefore, the bending moment distribution will be symmetrical about the midpoint of the
                    beam, and the maximum bending moment (M max ) is given by Eq. (2.15)
                                                 C           L
                                          M max =     a = b =                   (2.15)
                                                 2           2
                              U.S. Customary                      SI/Metric
                    Example 2. Calculate the shear force (V ) and  Example 2. Calculate the shear force (V ) and
                    bending moment (M) for a simply-supported  bending moment (M) for a simply-supported
                    beam with a concentrated couple (C) at a dis-  beam with a concentrated couple (C) at a dis-
                    tance (L/6) from the left end of the beam, where  tance (L/4) from the left end of the beam, where
                     C = 15 ft· kip = 15,000 ft · lb    F = 20 kN · m = 20,000 N · m
                                                                   1
                                                                          1
                      L = 12 ft, a = 4 ft, b = 8ft      L = 4m, a = 1 m, b = 2 m
                                                                   2      2
                    solution                           solution
                    Step 1. Establish the distance (x) from the left  Step 1. Establish the distance (x) from the left
                    end of the beam, where             end of the beam, where
                               L   12 ft                          L   4m
                            x =  =    = 2ft                    x =  =   = 1m
                               6    6                             4   4
                    Step 2. Determine the shear force (V ) from  Step 2. Determine the shear force (V ) from
                    Fig. 2.27 as                       Fig. 2.27 as
                               C  15,000 ft · lb                 C   20,000 N · m
                           V =   =                           V =   =
                               L     12 ft                       L      4m
                             = 1,250 lb                        = 5,000 N
                    Step 3. Determine the bending moment (M)  Step 3. Determine the bending moment (M)
                    from Eq. (2.13a).                  from Eq. (2.13a).
                           C    15,000 ft · 1b                C    20,000 N · m
                       M =   x =         (2ft)            M =   x =         (1m)
                            L      12 ft                      L       4m
                         = (1,250 lb)(2ft) = 2,500 ft · lb  = (5,000 N)(1m) = 5,000 N · m
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