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92  •  Chapter 3    /    The Structure of Crystalline Solids

                       EXAMPLE PROBLEM 3.15

                         Interplanar Spacing and Lattice Parameter Computations for Lead
                         Figure 3.24 shows an x-ray diffraction pattern for lead taken using a diffractometer and mono-
                         chromatic x-radiation having a wavelength of 0.1542 nm; each diffraction peak on the pattern
                         has been indexed. Compute the interplanar spacing for each set of planes indexed; also, de-
                         termine the lattice parameter of Pb for each of the peaks. For all peaks, assume the order of
                         diffraction is 1.

                         Solution
                         For each peak, in order to compute the interplanar spacing and the lattice parameter we must
                         employ Equations 3.21 and 3.22, respectively. The first peak of Figure 3.24, which results from
                         diffraction by the (111) set of planes, occurs at 2u   31.3 ; the corresponding interplanar spacing
                         for this set of planes, using Equation 3.21, is equal to

                                                   nl      (1)(0.1542 nm)
                                            d 111 =     =                = 0.2858 nm
                                                  2 sin u        31.3
                                                          (2)c sin a  b d
                                                                   2
                         And, from Equation 3.22, the lattice parameter a is determined as
                                                                2
                                                           2
                                                 a = d hkl 2h + k + l 2
                                                                   2
                                                             2
                                                   = d 111 2(1) + (1) + (1) 2
                                                   = (0.2858 nm)13 = 0.4950 nm
                         Similar computations are made for the next four peaks; the results are tabulated below:


                                           Peak Index     2U      d hkl (nm)  a(nm)
                                               200       36.6      0.2455     0.4910
                                               220       52.6      0.1740     0.4921
                                               311       62.5      0.1486     0.4929
                                               222       65.5      0.1425     0.4936





            3.17    NONCRYSTALLINE SOLIDS

            noncrystalline      It has been mentioned that noncrystalline solids lack a systematic and regular arrange-
                                ment of atoms over relatively large atomic distances. Sometimes such materials are also
            amorphous           called amorphous (meaning literally “without form”), or supercooled liquids, inasmuch
                                as their atomic structure resembles that of a liquid.
                                   An amorphous condition may be illustrated by comparison of the crystalline and
                                noncrystalline structures of the ceramic compound silicon dioxide (SiO 2 ), which may ex-
                                ist in both states. Figures 3.25a and 3.25b present two-dimensional schematic diagrams
                                for both structures of SiO 2 . Even though each silicon ion bonds to three oxygen ions
                                for both states, beyond this, the structure is much more disordered and irregular for the
                                noncrystalline structure.
                                   Whether a crystalline or an amorphous solid forms depends on the ease with which
                                a random atomic structure in the liquid can transform to an ordered state during so-
                                lidification. Amorphous materials, therefore, are characterized by atomic or molecular
                                structures that are relatively complex and become ordered only with some difficulty.
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