Page 126 - Mechanical Engineer's Data Handbook
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THERMODYNAMICS AND HEAT  TRANSFER                                                 115

          Velocity compounded impulse turbine

          One row of nozzles is followed by two or more rows of
          moving blades with intervening rows of fixed blades of
          the same type which alter the direction of flow.











                                                                     Ce.A
          Two-row wheel  Assume PI = P2, k = 1 and  that  all   Mass flow rate m=-
          blades are symmetrical.                                     V
                                                      Area of flow A=2nRmh















                                                                      \Maximom  efficiency
                                                                        diagram

                                                      50%  reaction  (Parson’s) turbine

             c,                                       In this case the velocity diagram is symmetrical.
          (exit velocitv)
                                                                     2nR,hC  sin a
                                                      Mass flow rate m=   V
          Maximum efficiency vmax =cosz a (at  p = y)   where: a= blade outlet angle.

                                                      Enthalpy drop per stage Ahs = C’p(2 cos a - p)
          in which case the steam leaves the last row axially.
                                                              Cb
                                                      where: p=-   and Cb=2nR,N.
          3.7.2   Impulse-reaction turbine                     C
          In this case there is ‘full admission’, i.e. e= 360”. Both   Stage power P,=mAh,
          nozzles and moving blades are similar in shape and          2p(2 cos a - p)
          have approximately the same enthalpy drop. Referring   Stage efficiency q, =  1 +p(2cosa-p)
          to the figure:
          Enthalpy drop  = (h, - h,) (for the fixed blades)   Maximum efficiency qmX =   2 cos2 a   (when p =cos a)
                     = (h, -h2) (for the moving blades)                    (1 + cos2 .)
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