Page 56 - Mechanical Engineers Reference Book
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Heat transfer  1145
                                            .
     In free (convection the  relationship  used  is Nu = ~(PY Gr)
     where Gv is the Grashof number, p2pgO13/p2 in which p is the
     coefficient  of  cubical  expansion  of  the  fluid  and  O  is  a
     temperature difference (usually surface to free stream tempe-
     rature).  The  transition  from  laminar  to  turbulent  flow  is
     determiined by  the product  (Pr . Gr) known  as the  Rayleigh
     number, Ra. As  a  simple example, for  plane  or cylindrical,
     vertical  surfaces it is found that;
     For Ra  < IO9, flow is laminar and Nu = O.59(Pr . Gr)0.25
     For Ra  > lo9, flow is turbulent  and Nu = 0.13(Pr. Gr)1’3
      The  1-epresentative  length  dimension  is  height  and  the
     resulting heat transfer  coefficients are average values for the
     whole  height.  Film temperature  is used  for fluid properties.
     Warnings similar to those given for forced convection apply to   Figure 1.73  Heat transfer by radiation betweer: two arbitrarily
     the use of  these equations.                  disposed grey surfaces
      Phase  change  convection  heat  transfer  (condensing  and
     evaporation)  shows  coefficients  that  are, in  general, higher
     than those found in single-phase flow. They are not discussed   the fraction of the energy emitted per unit time by one surface
     here bul. information  may be found in standard texts.   that is intercepted by another surface. The geometric factor is
                                                   given by
     1.7.3.3  Radiation                            Fl2  =  J AI j-
                                                               cos+,  cos+,  dAldA2
     When an emitting body is not surrounded by the receiver the   A?   TX2
     spatial distribution of energy from the radiating point needs to   It  can  be  seen  that  AIFlz = A*F2,,  a  useful  reciprocal
     be  known.  To  determine  this  distribution  the  intensity  of   relation.  It is also clear that the equation will require skill to
     radiation  id  is defined in any direction 4 as   solve  in  some  situations,  and  to  overcome  this  problem
                                                   geometric factors are available for many situations in tables or
                                                   on graphs (Hottel charts). The charts can give more informa-
                                                   tion than anticipated by the use of shape factor algebra, which
     where  dw is  a  small  solid  angle  subtended  at  the  radiatin   enables  factors  to  be  found  by  addition,  subtraction,  etc.
     point  by  the  area  i2tercepting  the  radiation,  dw  = dA/ $   (Figure 1.74).
     (Figure  1.72) (the solid angle represented by  a sphere is 47r   Having established the intensity of radiation and the geome-
     steradiains).  Lambert’s  iaw  of  diffuse  radiation  states  that   tric factor, problems  may be solved by  an electrical  analogy
     i,  = in cos 4 where  in  is  the  normal  intensity  of  radiation   using  the  radiosity  of  a  surface.  Radiosity  is  defined  as  the
     which can be determined for black  and grey bodies;   total emitted energy from a grey surface:
     Black in rp/.ir   Grey in mpln                J  = p; + p&
      With  this  knowledge  of  the  radiation  intensity  in  any   where .?’  is the radiosity  and,p&  the reflected portion  of  the
     direction it is only necessary to determine the amount that any   incident radiation G. Since E:  = &E{ the net rate of radiation
     body cain see of  any other body to calculate the heat transfer   leaving a grey surface of  area A becomes
     rate. For this purely geometric problem mathematical analysis
     (Figure  1.73)  suggests  a  quantity  variously  known  as  the
     geometric, configuration or shape €actor, which is defined as   p/A  E
                                                   which  may  be  envisaged  as  a  potential  difference,  &[  - 2,
                                                   divided by  a resistance, p/AE. A similar geometric resistance
                                                   of  1IAF can be established to enable  complete circuits to be
                        Small area ciA             drawn  up.  Thus  for  a  three-body  problem  we  may  sketch
                         receiving radiation       the  analogous electrical circuit (Figure 1.75) and apply Kirch-
                        from S                     hoff‘s  electric  current  law  to  each  s’ node  to  obtain  three
                                                   simultaneous equations of  the form
                                                   E{,-$    3-4  p 3-  p 1
                                                          +-+--          -0
                                                    P1IA1EI   1IA1F12   1IA1F13
                                                   If  there are more than three bodies  sketching becomes  com-
                                                    plex and the equation above can be rearranged  and genera-
                                                   lized. For N  surfaces (j = 1 to N) there will be N  equations,
                                                    the ith of  which (i = 1 to N) will be
                                                                “j
                                                    Yi - (1 - E!)   Fij$  = qEb,
                                                               ,=1
                       subtended by d.4            When j  = i, Fli will be zero unless the the surface is concave
                       at S                         and can see itself. This set of N simultaneous equations may be
                                                   solved by Gaussian elimination for which a computer program
     Figure 1.72  Spatial distribution of  radiation   may be used. The output of the solution will be N values of S‘
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